如果 URL 包含 puppeteer 中的函数 [英] if URL contains function in puppeteer

问题描述

因此，如果 URL 包含以下内容，我会尝试让我的代码执行某些操作:https://kith.com/throttle/queue?

So I am trying to have my code do something if the URL contains this: https://kith.com/throttle/queue?

在?"之后可以有任何东西，所以我只希望它识别https://kith.com/throttle/queue?"

After the '?' there can be anything, so I only want it to identify 'https://kith.com/throttle/queue?'

我正在使用 puppeteer 并希望它像这样工作:如果 URL 包含https://kith.com/throttle/queue?"然后等到它通过队列 (page.waitForNavigation({ waitUntil: 'networkidle2' }) 将等待它通过队列

I am using puppeteer and want it to work like this: If the URL contains 'https://kith.com/throttle/queue?' then wait until it passes the queue (page.waitForNavigation({ waitUntil: 'networkidle2' }) would work for waiting until it's through the queue

Else(如果 URL 不包含):什么都不做，转到下一行代码

Else (If the URL doesn't contain that): do nothing and go to the next line of code

推荐答案

这个网址很难理解，但是如果这是当前页面的网址，你可以试试这个:

It is hard to understand how do you get this URL, but if this is a URL of a current page, you can try this:

const url = await page.evaluate(() => location.href);

if(url.startsWith('https://kith.com/throttle/queue?')) {
  // Wait for navigation.
} else {
  // Do nothing.
}

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