如何遍历超市网站并获取产品名称和价格? [英] How to iterate through a supermarket website and getting the product name and prices?

问题描述

我试图从超市网站上获取所有类别的所有产品名称和价格，我找到的所有教程都只针对一个 const url，我需要遍历所有这些.到目前为止，我已经得到了这个

Im trying to obtain all the product name and prices from all the categories from a supermarket website, all the tutorials that i have found do it just for one const url, i need to iterate through all of them. So far i have got this

const puppeteer = require('puppeteer');

async function scrapeProduct(url) {
    const browser = await puppeteer.launch();
    const page = await browser.newPage();
    await page.goto(url);

    const [el2] = await page.$x('//*[@id="product-nonfood-page"]/main/div/div/div[1]/div[1]/div/div[2]/h1/div');
    const text2 = await el2.getProperty('textContent');
    const name = await text2.jsonValue();

    const [el] = await page.$x('//*[@id="product-nonfood-page"]/main/div/div/div[1]/div[1]/div/div[2]/div[2]/div[1]/div[2]/p[1]/em[2]/strong/text()');
    const text = await el.getProperty('textContent');
    const price = await text.jsonValue();

    console.log({name,price});

    await browser.close();
}

scrapeProduct('https://www.jumbo.com.ar/gaseosa-sprite-sin-azucar-lima-limon-1-25-lt/p'); 

仅适用于一个.我使用 nodejs 和 puppeteer.我怎样才能做到这一点?

which works just for one. Im using nodejs and puppeteer. How can i achieve this?

推荐答案

您可以尝试 for...of 循环，使用单个浏览器实例和单个页面，这样爬虫可能不会过载服务器:

You can try for...of loop, using a single browser instance and a single page so that the scraper might not overload the server:

const puppeteer = require('puppeteer');

(async function main() {
  try {
    const browser = await puppeteer.launch();
    const [page] = await browser.pages();

    const urls = [
      'https://www.jumbo.com.ar/gaseosa-sprite-sin-azucar-lima-limon-1-25-lt/p',
      // ...
    ];

    for (const url of urls) {
      await page.goto(url);

      const [el2] = await page.$x('//*[@id="product-nonfood-page"]/main/div/div/div[1]/div[1]/div/div[2]/h1/div');
      const text2 = await el2.getProperty('textContent');
      const name = await text2.jsonValue();

      const [el] = await page.$x('//*[@id="product-nonfood-page"]/main/div/div/div[1]/div[1]/div/div[2]/div[2]/div[1]/div[2]/p[1]/em[2]/strong/text()');
      const text = await el.getProperty('textContent');
      const price = await text.jsonValue();

      console.log({name,price});
    }

    await browser.close();
  } catch (err) {
    console.error(err);
  }
})();

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