如何在 Pygame 中使用 Sprite Collide [英] How to Use Sprite Collide in Pygame

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本文介绍了如何在 Pygame 中使用 Sprite Collide的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在制作一个非常简单的游戏,小鸟(玩家)必须躲避岩石,如果它被岩石击中,你就输了.我正在尝试使用 pygame.sprite.collide_rect() 来判断它们是否接触过,但我似乎无法弄清楚如何正确使用它.

I am making a very simple game where the bird (player) has to dodge the rock and if it gets hit by the rock you lose. I am trying to use pygame.sprite.collide_rect() to tell if they touched but I cant seem to figure how to correctly use it.

这是我的代码:

import pygame
import os, sys
import random
import time

img_path = os.path.join('C:\Python27', 'player.png')
img_path2 = os.path.join('C:\Python27', 'rock.png')

class Bird(object):  
    def __init__(self):           
        self.image_s = pygame.image.load(img_path)
        self.image_b = self.image_s.get_rect()
        self.x = 0
        self.y = 0

    def handle_keys(self):
        key = pygame.key.get_pressed()
        dist = 2 
        if key[pygame.K_DOWN]:
            self.y += dist 
        elif key[pygame.K_UP]: 
            self.y -= dist
        if key[pygame.K_RIGHT]: 
            self.x += dist 
        elif key[pygame.K_LEFT]:
            self.x -= dist 

   def draw(self, surface):
       surface.blit(self.image, (self.x, self.y))

    def background(self, surface):
        bg = os.path.join('C:\Python27', 'bg.png')
        self.image2 = pygame.image.load(bg)
        surface.blit(self.image2, (0,0))

class Rock(object): 
    def __init__(self, x=640, y=0,):
        self.image_s = pygame.image.load(img_path2)
        self.image_b = self.image_s.get_rect()
        self.x = x
        self.y = y
        dist = 10
        self.dist = dist

    def rock(self):
        dist = 10
        self.x -=dist

    def rock_draw(self, surface):
        surface.blit(self.image, (self.x, self.y))

    def checkCollision(sprite1, sprite2):
        col = pygame.sprite.collide_rect(sprite1, sprite2)
        if col == True:
            sys.exit()

pygame.init()
screen = pygame.display.set_mode((640, 200))

bird = Bird() 
rock = Rock()
clock = pygame.time.Clock()


running = True
while running:

    for event in pygame.event.get():
       if event.type == pygame.QUIT:
            pygame.quit()
            running = False

        if rock.x < 0:
            y = random.randint(10, 190)
            rock = Rock(640, y)
        rock.checkCollision(bird.image_b, rock.image_b)

    bird.handle_keys()     
    rock.rock()

    screen.fill((255,255,255))
    bird.background(screen)
    bird.draw(screen)
    rock.rock_draw(screen)
    pygame.display.update() 

    clock.tick(40)

当我尝试运行它时,它告诉我它只需要 2 个参数,当我尝试修复时我给出了 3 个参数,因为我收到了各种不同的错误消息.

When I try to run it it tells me it only takes 2 arguments and I gave three when I try to fix that I get all kinds of different error messages.

推荐答案

def checkCollision(sprite1, sprite2):
    col = pygame.sprite.collide_rect(sprite1, sprite2)
    if col == True:
        sys.exit()

应该

def checkCollision(self, sprite1, sprite2):
    col = pygame.sprite.collide_rect(sprite1, sprite2)
    if col == True:
        sys.exit()

因为它是绑定到对象的方法.

since it's a method bound to an object.

这篇关于如何在 Pygame 中使用 Sprite Collide的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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