如何在 Pygame 中使用 Sprite Collide [英] How to Use Sprite Collide in Pygame
本文介绍了如何在 Pygame 中使用 Sprite Collide的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在制作一个非常简单的游戏,小鸟(玩家)必须躲避岩石,如果它被岩石击中,你就输了.我正在尝试使用 pygame.sprite.collide_rect() 来判断它们是否接触过,但我似乎无法弄清楚如何正确使用它.
I am making a very simple game where the bird (player) has to dodge the rock and if it gets hit by the rock you lose. I am trying to use pygame.sprite.collide_rect() to tell if they touched but I cant seem to figure how to correctly use it.
这是我的代码:
import pygame
import os, sys
import random
import time
img_path = os.path.join('C:\Python27', 'player.png')
img_path2 = os.path.join('C:\Python27', 'rock.png')
class Bird(object):
def __init__(self):
self.image_s = pygame.image.load(img_path)
self.image_b = self.image_s.get_rect()
self.x = 0
self.y = 0
def handle_keys(self):
key = pygame.key.get_pressed()
dist = 2
if key[pygame.K_DOWN]:
self.y += dist
elif key[pygame.K_UP]:
self.y -= dist
if key[pygame.K_RIGHT]:
self.x += dist
elif key[pygame.K_LEFT]:
self.x -= dist
def draw(self, surface):
surface.blit(self.image, (self.x, self.y))
def background(self, surface):
bg = os.path.join('C:\Python27', 'bg.png')
self.image2 = pygame.image.load(bg)
surface.blit(self.image2, (0,0))
class Rock(object):
def __init__(self, x=640, y=0,):
self.image_s = pygame.image.load(img_path2)
self.image_b = self.image_s.get_rect()
self.x = x
self.y = y
dist = 10
self.dist = dist
def rock(self):
dist = 10
self.x -=dist
def rock_draw(self, surface):
surface.blit(self.image, (self.x, self.y))
def checkCollision(sprite1, sprite2):
col = pygame.sprite.collide_rect(sprite1, sprite2)
if col == True:
sys.exit()
pygame.init()
screen = pygame.display.set_mode((640, 200))
bird = Bird()
rock = Rock()
clock = pygame.time.Clock()
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
running = False
if rock.x < 0:
y = random.randint(10, 190)
rock = Rock(640, y)
rock.checkCollision(bird.image_b, rock.image_b)
bird.handle_keys()
rock.rock()
screen.fill((255,255,255))
bird.background(screen)
bird.draw(screen)
rock.rock_draw(screen)
pygame.display.update()
clock.tick(40)
当我尝试运行它时,它告诉我它只需要 2 个参数,当我尝试修复时我给出了 3 个参数,因为我收到了各种不同的错误消息.
When I try to run it it tells me it only takes 2 arguments and I gave three when I try to fix that I get all kinds of different error messages.
推荐答案
def checkCollision(sprite1, sprite2):
col = pygame.sprite.collide_rect(sprite1, sprite2)
if col == True:
sys.exit()
应该
def checkCollision(self, sprite1, sprite2):
col = pygame.sprite.collide_rect(sprite1, sprite2)
if col == True:
sys.exit()
因为它是绑定到对象的方法.
since it's a method bound to an object.
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