使用 pygame.mixer 创建播放列表 [英] Create a playlist using pygame.mixer
本文介绍了使用 pygame.mixer 创建播放列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我一直在尝试制作一个简单的播放列表,一个接一个播放 3 首歌曲,下面的代码显示了这种尝试.它不会播放第一首歌曲 music1.mp3,而是播放最后一首歌曲 music3.mp3 并停止播放.我曾尝试查看类似的问题,但一直在努力寻找解决方案.
I have been trying to make a simple playlist that plays 3 songs one after the other the code below shows an attempt of that. Rather than playing the first song music1.mp3 it plays the last song music3.mp3 and stops playing. I have tried looking at similar questions but strugling to find a soloution.
如果有人可以帮助我提供一些建议或指导,我们将不胜感激.
Please if anyone can help give me some advice or some guidance it will be much appreciated.
迈克
import pygame
import time
pygame.mixer.init()
pygame.display.init()
screen = pygame.display.set_mode ( ( 420 , 240 ) )
playlist = list()
playlist.append ( "music1.mp3" )
playlist.append ( "music2.mp3" )
playlist.append ( "music3.mp3" )
pygame.mixer.music.load ( playlist.pop() ) # Get the first track from the playlist
pygame.mixer.music.queue ( playlist.pop() ) # Queue the 2nd song
pygame.mixer.music.set_endevent ( pygame.USEREVENT ) # Setup the end track event
pygame.mixer.music.play() # Play the music
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.USEREVENT: # A track has ended
if len ( playlist ) > 0: # If there are more tracks in the queue...
pygame.mixer.music.queue ( playlist.pop() ) # Queue the next one in the list
推荐答案
list.pop() 返回列表中的最后一项.如果你改变了:
list.pop() returns the last item in the list. If you changed:
playlist.append ( "music1.mp3" )
playlist.append ( "music2.mp3" )
playlist.append ( "music3.mp3" )
到
playlist.append ( "music3.mp3" )
playlist.append ( "music2.mp3" )
playlist.append ( "music1.mp3" )
然后它会正常工作.
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