pyodbc 不会引发 SQL Server 错误 [英] pyodbc does not throw on SQL Server error

问题描述

我正在尝试使用 pyodbc(使用 Python 2.7)调用存储过程将记录插入到 SQL Server 2012 表中.我正在传递一个临时表.

I am trying to use pyodbc (with Python 2.7) to call a stored procedure to insert records into a SQL Server 2012 table. I am passing a temporary table.

我转储了我的 sql，当通过 SQL Server 管理控制台执行时，它生成了以下外键错误:

I dumped out my sql and when executed through the SQL Server Management console, it generated the following Foreign Key error:

Msg 547, Level 16, State 0, Procedure spInsertBondTickerValues, Line 26
The INSERT statement conflicted with the FOREIGN KEY constraint "FK__BondTickerValue__756D6ECB".
The conflict occurred in database "QuantDev", table "dbo.Tickers".
The statement has been terminated.

然而，pyodbc 没有引发异常.我将如何测试生成的游标或连接以了解发生了问题，以及如何获取错误消息?

However, pyodbc did not raise an exception. How would I test the resulting cursor or connection to know that a problem occurred, and how do I get the error message?

非常感谢.

编辑这里是完整的sql文本:

EDIT Here is the full sql text:

DECLARE @rawTbl [dbo].TickerValueTableType
INSERT INTO @rawTbl (Ticker, BBName, LastValue, ValueTime, SourceDescr) VALUES
('IBM', 'Equity', 179.230000, '2013-11-01 00:00:00.000000', 'Bloomberg'),
('SPX', 'Index', 1803.710000, '2013-12-10 00:00:00.000000', 'Bloomberg')
EXEC [dbo].spInsertBondTickerValues @rawTbl

EDIT 2 这是相关的 Python 代码:

EDIT 2 Here is the relevant Python code:

def execSQLwithCommit(self, sql):
    cursor = self.conn.cursor()
    cursor.execute(sql)
    self.conn.commit()

先前通过以下方式建立的连接

where the connection has been previously made via

self.conn = pyodbc.connect(app      = appName,
                           driver   = '{SQL Server Native client 11.0}',
                           server   = server,
                           database = db,
                           Trusted_Connection = 'yes')

推荐答案

我能够使用以下代码重新创建您的问题，但无提示地失败了:

I was able to recreate your issue using the following code, which fails silently:

import pyodbc
cnxn = pyodbc.connect('DSN=myDb;')
cursor = cnxn.cursor()
sql = """   
DECLARE @rawTbl dbo.ClientAddressInputType;
INSERT INTO @rawTbl (ClientID, Addr1) VALUES 
(2, 'higgy'), 
(3, 'jiggy'); 
EXEC dbo.AddClientAddress @rawTbl
"""
cursor.execute(sql)
cursor.commit()
cnxn.close()

但是，我可以通过在 sql 的开头简单地添加 SET NOCOUNT ON; 来让代码抛出适当的 IntegrityError 异常字符串:

However, I can get the code to throw the appropriate IntegrityError exception by simply adding SET NOCOUNT ON; at the beginning of the sql string:

import pyodbc
cnxn = pyodbc.connect('DSN=myDb;')
cursor = cnxn.cursor()
sql = """   
SET NOCOUNT ON;
DECLARE @rawTbl dbo.ClientAddressInputType;
INSERT INTO @rawTbl (ClientID, Addr1) VALUES 
(2, 'higgy'), 
(3, 'jiggy'); 
EXEC dbo.AddClientAddress @rawTbl
"""
cursor.execute(sql)
cursor.commit()
cnxn.close()

导致

Traceback (most recent call last):
  File "C:\Users\Gord\Desktop\pyOdbc.py", line 12, in <module>
    cursor.execute(sql)
IntegrityError: ('23000', '[23000] [Microsoft][SQL Server Native Client 10.0][SQL Server]The INSERT statement conflicted with the FOREIGN KEY constraint "FK_ClientAddresses_Clients". The conflict occurred in database "myDb", table "dbo.Clients", column \'ClientID\'. (547) (SQLExecDirectW); [01000] [Microsoft][SQL Server Native Client 10.0][SQL Server]The statement has been terminated. (3621)')

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