pyqt使用线程更新进度条 [英] pyqt updating progress bar using thread

问题描述

我想使用线程方法从我的 main.py 更新进度条.

I want to update the progress bar from my main.py using thread approach.

if __name__ == "__main__":

       app = QApplication(sys.argv)
       uiplot = gui.Ui_MainWindow()

       Update_Progressbar_thread = QThread() 
       Update_Progressbar_thread.started.connect(Update_Progressbar)


       def Update_Progressbar():
              progressbar_value = progressbar_value + 1
              while (progressbar_value < 100):
                     uiplot.PSprogressbar.setValue(progressbar_value)
                     time.sleep(0.1)
      uiplot.PSStart_btn.clicked.connect(Update_Progressbar_thread.start) 

问题是这种方法干扰了我的 GUI，我无法点击任何按钮等.

The problem is this approach james my GUI and I cannot click any buttons etc.

或者我怎样才能让它工作?谢谢

Alternatively how can I make it work ? Thanks

推荐答案

说明:

根据您的逻辑，您将在 QThread 启动时调用Update_Progressbar"来运行，但是Update_Progressbar"将在哪里运行?好吧，在阻塞 GUI 的主线程中.

With your logic you are invoking "Update_Progressbar" to run when the QThread starts, but where will "Update_Progressbar" run? Well, in the main thread blocking the GUI.

解决方案:

您的目标不是在 QThread 启动时运行Update_Progressbar"，而是在处理 QThread 的线程中运行.因此，在这种情况下，您可以创建一个驻留在 QThread 处理的线程中的 Worker

Your goal is not to run "Update_Progressbar" when the QThread starts but to run in the thread that handles QThread. So in this case you can create a Worker that lives in the thread handled by QThread

class Worker(QObject):
    progressChanged = pyqtSignal(int)

    def work(self):
        progressbar_value = 0
        while progressbar_value < 100:
            self.progressChanged.emit(progressbar_value)
            time.sleep(0.1)


if __name__ == "__main__":

    app = QApplication(sys.argv)
    uiplot = gui.Ui_MainWindow()

    thread = QThread()
    thread.start()

    worker = Worker()
    worker.moveToThread(thread)
    worker.progressChanged.connect(uiplot.PSprogressbar.setValue)
    uiplot.PSStart_btn.clicked.connect(worker.work)

    # ...

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