目的-C-＆GT; JSON-＆GT; PHP数组 [英] Objective-C->JSON->PHP Array

问题描述

我一直在挣扎与本作的最后几天;我想发布一个数组到PHP。我可以成功发送，但它不是一个后可变（我尝试使用可变密钥JSON......有了这个code，我收到PHP中的数组拍摄于：

目标-C

  NSError *错误;
的NSDictionary * jsonDictionary = [NSDictionary的dictionaryWithObjects：[NSArray的arrayWithObjects：@一，@二，@三，零] forKeys：[NSArray的arrayWithObjects：@一，@B，@C，零]];
NSArray的* jsonArray = [NSArray的arrayWithObject：jsonDictionary];
NSData的* jsonData = [NSJSONSerialization dataWithJSONObject：jsonArray选项：NSUTF8StringEncoding错误：＆放大器;错误]
NSMutableURLRequest *请求= [NSMutableURLRequest requestWithURL：[NSURL URLWithString：@？somewebservicelocation / arrayTest.php JSON =]];
[申请的setValue：@应用程序/ JSONforHTTPHeaderField：@的Content-Type];
[要求setHTTPMethod：@POST];
[要求setHTTPBody：jsonData];
NSData的* returnData = [NSURLConnection的sendSynchronousRequest：要求returningResponse：无错误：无];
* NSString的响应= [[NSString的页头] initWithData：returnData编码：NSUTF8StringEncoding];
的NSLog（@回应：％@，响应）;
 

PHP

  $ =处理的fopen（'PHP：//输入'，'R'）;
    $阵列=与fgets（$处理）;
    回声$阵列;
    如果（使用isset（$阵列））
    {
        回声成功;
    }
    其他
    {
        回声失败;
    }
 

如果我用这个PHP，使用_POST，我没有得到任何的爱：

  $ rawJsonData = $ _ POST ['JSON'];
$阵列= json_de code（的stripslashes（$ rawJsonData），TRUE）;
回声$阵列;
如果（使用isset（$阵列））
{
    回声成功;
}
其他
{
    回声失败;
}
 

...我已经在这几天 - 遍布堆栈溢出，并理解我需要包括在请求体中的变量和数据，但我不能得到它的工作。我究竟做错了什么？你怎么去这个不同？从这个头痛救我......

解决方案

在PHP端，我用类似的东西到你的第一个例子：

 ＆LT; PHP$处理=的fopen（PHP：//输入，RB）;
$ HTTP_RAW_POST_DATA ='';
而（！的feof（$处理））{
    。$ HTTP_RAW_POST_DATA = FREAD（$处理，8192）;
}
FCLOSE（$处理）;//做你想要做什么用
//
//用于诊断目的，我只是要取消code，确保我有一个数组，
//和JSON，包括状态，code，和原来的请求作出响应$ post_data = json_de code（$ HTTP_RAW_POST_DATA，真正的）;如果（is_array（$ post_data））
    $响应=阵列（状态=＆gt;中确定，code=大于0，原始请求=＆GT; $ post_data）;
其他
    $响应=阵列（状态=＆gt;中的错误，code= -1个，original_request=＆GT; $ post_data）;$处理= json_en code（$响应）;
回声$处理;？＆GT;
 

然后在iOS方面，我使用：

<为pre> //创建字典（或阵列）*的NSDictionary字典= @ {@一：@一，@B：@二，@C：@三};
NSError *误差=零;
NSData的*数据= [NSJSONSerialization dataWithJSONObject：字典选项：0错误：＆放大器;错误]
如果（错误）
    的NSLog（@％S：JSON EN code错误：％@，__FUNCTION__，错误）;//创建请求NSURL * URL = [NSURL URLWithString：@your.url.here];
NSMutableURLRequest *请求= [NSMutableURLRequest requestWithURL：URL]
[要求setHTTPMethod：@POST];
[申请的setValue：@应用程序/ JSON的;字符集= UTF-8forHTTPHeaderField：@的Content-Type];
[要求setHTTPBody：数据]//发出请求NSURLResponse *响应=零;
NSData的* returnData = [NSURLConnection的sendSynchronousRequest：请求returningResponse：安培;响应错误：放大器;错误]
如果（错误）
    的NSLog（@％S：NSURLConnection的错误：％@，__FUNCTION__，错误）;//检查响应* NSString的responseString = [[NSString的页头] initWithData：returnData编码：NSUTF8StringEncoding];
的NSLog（@responseString：％@，responseString）;


我刚刚测试了这个往返，并能正常工作。

---

如果你有决心使用 _ POST 技术，有什么工作对我来说是设置中的数据是 JSON =％@ ，如：

 的NSDictionary *词典= ...
NSData的*数据= [NSJSONSerialization dataWithJSONObject：字典选项：0错误：＆放大器;错误]
* NSString的字符串= [[NSString的页头] initWithData：数据编码：NSUTF8StringEncoding];
如果（错误）
    的NSLog（@％S：JSON EN code错误：％@，__FUNCTION__，错误）;NSURL * URL = [NSURL URLWithString：@your.url.here];
NSMutableURLRequest *请求= [NSMutableURLRequest requestWithURL：URL][要求setHTTPMethod：@POST];
* NSString的PARAMS = [的NSString stringWithFormat：@JSON =％@，
                    [字符串stringByAddingPercentEscapesUsingEncoding：NSUTF8StringEncoding]];
NSData的* paramsData = [PARAMS dataUsingEncoding：NSUTF8StringEncoding];
[申请的addValue：@8位forHTTPHeaderField：@内容传输编码];
[申请的addValue：@应用程序/ x-WWW的形式urlen codeDforHTTPHeaderField：@的Content-Type];
[要求setHTTPBody：paramsData];//现在发送请求，像前
 

和PHP的解析它很像你有：

  $ HTTP_RAW_POST_DATA = $ _ POST ['JSON'];$ post_data = json_de code（的stripslashes（$ HTTP_RAW_POST_DATA），TRUE）;如果（is_array（$ post_data））
    $响应=阵列（状态=＆gt;中确定，code=大于0，原始请求=＆GT; $ post_data）;
其他
    $响应=阵列（状态=＆gt;中的错误，code= -1个，original_request=＆GT; $ post_data）;$处理= json_en code（$响应）;
回声$处理;
 

I've been struggling with this for the last few days; I am trying to post an array to PHP. I can successfully send it, but it's not taken in with a post-variable (I am trying to use the variable key "json"... With this code, I receive the array in php:

Objective-C

NSError *error;
NSDictionary *jsonDictionary = [NSDictionary dictionaryWithObjects:[NSArray arrayWithObjects: @"one", @"two", @"three", nil] forKeys: [NSArray arrayWithObjects: @"a", @"b", @"c", nil]];
NSArray *jsonArray = [NSArray arrayWithObject:jsonDictionary];
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:jsonArray options:NSUTF8StringEncoding error:&error];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:@"somewebservicelocation/arrayTest.php?json="]];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:jsonData];
NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSString *response = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
NSLog(@"response: %@",response);

PHP

$handle = fopen('php://input','r');
    $array = fgets($handle);
    echo $array;
    if(isset($array))
    {
        echo "success";
    }
    else
    {
        echo "failure";
    }

If I use this PHP, using _POST, I get no love:

$rawJsonData = $_POST['json'];
$array = json_decode(stripslashes($rawJsonData),true);
echo $array;
if(isset($array))
{
    echo "success";
}
else
{
    echo "failure";
}

...I've been at it for several days - all over Stack Overflow, and understand I need to include the variable and data in the body of the request, but I just can't get it to work. What am I doing wrong? How do you go about this differently? Save me from this headache...

解决方案

On the PHP side, I've used something similar to your first example:

<?php

$handle = fopen("php://input", "rb");
$http_raw_post_data = '';
while (!feof($handle)) {
    $http_raw_post_data .= fread($handle, 8192);
}
fclose($handle);

// do what you want with it
//
// For diagnostic purposes, I'm just going to decode, make sure I got an array, 
// and respond with JSON that includes status, code, and the original request

$post_data = json_decode($http_raw_post_data,true);

if (is_array($post_data))
    $response = array("status" => "ok", "code" => 0, "original request" => $post_data);
else
    $response = array("status" => "error", "code" => -1, "original_request" => $post_data);

$processed = json_encode($response);
echo $processed;

?>

And then on the iOS side, I use:

// create the dictionary (or array)

NSDictionary *dictionary = @{@"a": @"One", @"b": @"Two", @"c": @"Three"};
NSError *error = nil;
NSData *data = [NSJSONSerialization dataWithJSONObject:dictionary options:0 error:&error];
if (error)
    NSLog(@"%s: JSON encode error: %@", __FUNCTION__, error);

// create the request

NSURL *url = [NSURL URLWithString:@"your.url.here"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
[request setHTTPMethod:@"POST"];
[request setValue:@"application/json; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:data];

// issue the request

NSURLResponse *response = nil;
NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
if (error)
    NSLog(@"%s: NSURLConnection error: %@", __FUNCTION__, error);

// examine the response

NSString *responseString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
NSLog(@"responseString: %@",responseString);

I just tested this round trip, and it works fine.

---

If you are determined to use the _POST technique, what works for me is to set the the data to be json=%@, such as:

NSDictionary *dictionary = ...
NSData *data = [NSJSONSerialization dataWithJSONObject:dictionary options:0 error:&error];
NSString *string = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
if (error)
    NSLog(@"%s: JSON encode error: %@", __FUNCTION__, error);

NSURL *url = [NSURL URLWithString:@"your.url.here"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];

[request setHTTPMethod:@"POST"];
NSString *params = [NSString stringWithFormat:@"json=%@",
                    [string stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
NSData *paramsData = [params dataUsingEncoding:NSUTF8StringEncoding];
[request addValue:@"8bit" forHTTPHeaderField:@"Content-Transfer-Encoding"];
[request addValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody:paramsData];

// now send the request, like before

And the PHP to parse it is much like you had:

$http_raw_post_data = $_POST['json'];

$post_data = json_decode(stripslashes($http_raw_post_data),true);

if (is_array($post_data))
    $response = array("status" => "ok", "code" => 0, "original request" => $post_data);
else
    $response = array("status" => "error", "code" => -1, "original_request" => $post_data);

$processed = json_encode($response);
echo $processed;

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