使一个窗口出现在另一个窗口的顶部，阻止对其他窗口的访问，直到单击按钮 [英] Make a window appear on top of another, block access to other windows until button clicked

问题描述

Python 2.7，PyQt4.8.5

Python 2.7, PyQt4.8.5

我想要一个主应用程序窗口，然后是第二个弹出窗口来显示 com 端口设置.此窗口应始终位于父窗口的顶部，直到单击确定或取消按钮；关闭子窗口.(有点像必需的答案，即在您从子窗口中选择设置之前无法处理)

I want to have a main app window and then a second pop up window to display com port settings. This window should always be on top of the parent window until either the ok or the cancel button is clicked; closing the child window. (sort of like a required answer i.e. cant process until you choose the settings from the child window)

是否有 Python Qt 命令来执行此操作?

Is there a Python Qt command to do this?

抱歉，如果之前有人问过/回答过这个问题，我的搜索没有返回任何有用的信息.

Apologies if this has been asked/answered before, my search returned nothing useful.

推荐答案

你想要一个 模态对话框.例如:

You want a modal dialog. For example:

dialog = QInputDialog()
dialog.exec_()

您可以实现自己的对话框小部件(通过子类化 QDialog)或使用几个可用的其中之一.

You can either implement your own dialog widget (by subclassing QDialog) or use one of the several available.

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