在python中使用pyqt4的文件浏览器? [英] File browser using pyqt4 in python?

问题描述

我正在尝试创建桌面应用程序.我使用 pyqt4 设计器创建了一个按钮.然后将 .ui 转换为 .py 文件.我创建的按钮应该用作文件选择器.我发现很难向其中添加文件浏览器.任何人都可以帮我解决这个问题.

我试过的代码

<块引用>

def setupUi(self, WizardPage):WizardPage.setObjectName(_fromUtf8("WizardPage"))WizardPage.resize(636, 486)self.horizo​​ntalLayoutWidget = QtGui.QWidget(WizardPage)self.groupBox = QtGui.QGroupBox(self.horizo​​ntalLayoutWidget)self.groupBox.setObjectName(_fromUtf8("groupBox"))self.pushButton = QtGui.QPushButton(self.groupBox)

def retranslateUi(self, WizardPage):WizardPage.setWindowTitle(_translate("WizardPage", "WizardPage", None))self.groupBox.setTitle(_translate("WizardPage", "SOURCE", None))self.pushButton.setText(_translate("WizardPage", "点击我！", None))self.pushButton.clicked.connect(self.pushButton_Clicked)def pushButton_Clicked(self, WizardPage):文件名 = QtGui.QFileDialog.getOpenFileName(self)

请指导我哪里出错了?

解决方案

首先，从不直接编辑pyuic创建的.py文件代码>.相反，将其导入您的主程序，或者(我的首选方法，让您更有效率)使用 uic 模块(从 PyQt 导入，from PyQt4 import uic.) ui = uic.loadUi('example.ui') 将导入 UI 文件.

但是，要解决您的问题，您需要更改一些内容.

openfile = QtGui.QFileDialog.getOpenFileName(self) # 文件名行f = open(openfile, 'r') # 新行data = f.read() # 换行

I am trying to create desktop app. I have created a button using pyqt4 designer.Then converted .ui to .py file. Button which i have created should work as file picker. I am finding difficult to add file browser to that.Can any one help me regarding this.

Code i tried

def setupUi(self, WizardPage):
        WizardPage.setObjectName(_fromUtf8("WizardPage"))
        WizardPage.resize(636, 486)
        self.horizontalLayoutWidget = QtGui.QWidget(WizardPage)
        self.groupBox = QtGui.QGroupBox(self.horizontalLayoutWidget)
        self.groupBox.setObjectName(_fromUtf8("groupBox"))
        self.pushButton = QtGui.QPushButton(self.groupBox)

def retranslateUi(self, WizardPage):
    WizardPage.setWindowTitle(_translate("WizardPage", "WizardPage", None))
    self.groupBox.setTitle(_translate("WizardPage", "SOURCE", None))
    self.pushButton.setText(_translate("WizardPage", "Click Me!", None))
    self.pushButton.clicked.connect(self.pushButton_Clicked)

def pushButton_Clicked(self, WizardPage):
    filename = QtGui.QFileDialog.getOpenFileName(self)

Please guide me where i am going wrong?

解决方案

First of all, never directly edit the .py file created by pyuic. Instead, import it into your main program, or (my preferred method, makes you more productive) use the uic module (imported from PyQt with from PyQt4 import uic.) ui = uic.loadUi('example.ui') will import the UI file.

However, in resolution of your problem you need to change some things.

openfile = QtGui.QFileDialog.getOpenFileName(self) # Filename line
f = open(openfile, 'r') # New line
data = f.read() # New line

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