计算字符串中子字符串出现的次数 [英] Count number of occurrences of a substring in a string

问题描述

如何计算给定子字符串出现在 Python 字符串中的次数?

例如:

<预><代码>>>>'foo bar foo'.numberOfOccurrences('foo')2

解决方案

string.count(substring)，如:

<预><代码>>>>"abcdabcva".count("ab")2

更新:

正如评论中所指出的，这是针对非重叠出现的方法.如果您需要计算重叠出现的次数，最好在以下位置查看答案:"Python regex找到所有重叠的匹配项?"，或者查看我下面的其他答案.

How can I count the number of times a given substring is present within a string in Python?

For example:

>>> 'foo bar foo'.numberOfOccurrences('foo')
2

解决方案

string.count(substring), like in:

>>> "abcdabcva".count("ab")
2

Update:

As pointed up in the comments, this is the way to do it for non overlapping occurrences. If you need to count overlapping occurrences, you'd better check the answers at: "Python regex find all overlapping matches?", or just check my other answer below.

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