在C - 检查是否在字符数组存在一个char [英] In C - check if a char exists in a char array

问题描述

我想检查一个字符属于无效字符列表/数组。

I'm trying to check if a character belongs to a list/array of invalid characters.

这是一个Python背景的，我以前可以，只是说：

Coming from a Python background, I used to be able to just say :

for c in string:
    if c in invalid_characters:
        #do stuff, etc

我怎样才能做到这一点与常规的C字符数组？

How can I do this with regular C char arrays?

推荐答案

的等价的C code是这样的：

The equivalent C code looks like this:

#include <stdio.h>
#include <string.h>

// This code outputs: h is in "This is my test string"
int main(int argc, char* argv[])
{
   const char *invalid_characters = "hz";
   char *mystring = "This is my test string";
   char *c = mystring;
   while (*c)
   {
       if (strchr(invalid_characters, *c))
       {
          printf("%c is in \"%s\"\n", *c, mystring);
       }

       c++;
   }

   return 0;
}

注意INVALID_CHARACTERS是C字符串，即得。一个空值终止字符阵列。

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