Python 正则表达式 - 如何从通配符表达式中捕获多个组? [英] Python regular expressions - how to capture multiple groups from a wildcard expression?

问题描述

我有一个 Python 正则表达式，其中包含一个可以出现零次或多次的组 - 但是当我之后检索组列表时，只有最后一个出现.示例:

I have a Python regular expression that contains a group which can occur zero or many times - but when I retrieve the list of groups afterwards, only the last one is present. Example:

re.search("(\w)*", "abcdefg").groups()

这将返回列表 ('g',)

this returns the list ('g',)

我需要它返回 ('a','b','c','d','e','f','g',)

I need it to return ('a','b','c','d','e','f','g',)

这可能吗?我该怎么做?

Is that possible? How can I do it?

推荐答案

除了 Douglas Leeder 的解决方案，解释如下:

在正则表达式中，组数是固定的.将量词放在组后面不会增加组数(想象所有其他组索引都会增加，因为一个更早的组匹配不止一次).

In regular expressions the group count is fixed. Placing a quantifier behind a group does not increase group count (imagine all other group indexes increment because an eralier group matched more than once).

当需要多次匹配时，带有量词的组是使复杂子表达式原子化的方法.正则表达式引擎只能将最后一个匹配项仅保存到组中.简而言之:没有办法用单一的非武装"正则表达式来实现你想要的，你必须找到另一种方式.

Groups with quantifiers are the way of making a complex sub-expression atomic, when there is need to match it more than once. The regex engine has no other way than saving the last match only to the group. In short: There is no way to achieve what you want with a single "unarmed" regular expression, and you have to find another way.

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