产品代码看起来像abcd2343,用字母和数字分割什么 [英] Product code looks like abcd2343, what to split by letters and numbers
问题描述
我在一个文本文件中有一个产品代码列表,每个类似的产品代码如下所示:
I have a list of product codes in a text file, on each like is the product code that looks like:
abcd2343 abw34324 abc3243-23A
abcd2343 abw34324 abc3243-23A
所以它是字母后接数字和其他字符.
我想在第一次出现数字时拆分.
推荐答案
In [32]: import re
In [33]: s='abcd2343 abw34324 abc3243-23A'
In [34]: re.split('(\d+)',s)
Out[34]: ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A']
或者,如果您想在第一次出现数字时进行拆分:
Or, if you want to split on the first occurrence of a digit:
In [43]: re.findall('\d*\D+',s)
Out[43]: ['abcd', '2343 abw', '34324 abc', '3243-', '23A']
<小时>
\d+
匹配 1 个或多个数字.\d*\D+
匹配 0 个或多个数字后跟 1 个或多个非数字.\d+|\D+
匹配 1 个或多个数字或 1 个或多个非数字.\d+
matches 1-or-more digits.\d*\D+
matches 0-or-more digits followed by 1-or-more non-digits.\d+|\D+
matches 1-or-more digits or 1-or-more non-digits.
请参阅文档,了解有关 Python 正则表达式的更多信息语法.
Consult the docs for more about Python's regex syntax.
re.split(pat, s)
将使用 pat
作为分隔符分割字符串 s
.如果pat
以括号开头和结尾(从而成为捕获组"),则re.split
将返回pat
匹配的子串> 还有.例如,比较:
re.split(pat, s)
will split the string s
using pat
as the delimiter. If pat
begins and ends with parentheses (so as to be a "capturing group"), then re.split
will return the substrings matched by pat
as well. For instance, compare:
In [113]: re.split('\d+', s)
Out[113]: ['abcd', ' abw', ' abc', '-', 'A'] # <-- just the non-matching parts
In [114]: re.split('(\d+)', s)
Out[114]: ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A'] # <-- both the non-matching parts and the captured groups
相反,re.findall(pat, s)
只返回s
中与pat
匹配的部分:
In contrast, re.findall(pat, s)
returns only the parts of s
that match pat
:
In [115]: re.findall('\d+', s)
Out[115]: ['2343', '34324', '3243', '23']
因此,如果 s
以数字结尾,则可以使用 re.findall('\d+|\D+', s)
避免以空字符串结尾而不是 re.split('(\d+)', s)
:
Thus, if s
ends with a digit, you could avoid ending with an empty string by using re.findall('\d+|\D+', s)
instead of re.split('(\d+)', s)
:
In [118]: s='abcd2343 abw34324 abc3243-23A 123'
In [119]: re.split('(\d+)', s)
Out[119]: ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A ', '123', '']
In [120]: re.findall('\d+|\D+', s)
Out[120]: ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23', 'A ', '123']
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