将字符串拆分为大小均匀的块 [英] Split a string to even sized chunks

问题描述

我如何能够接受像 'aaaaaaaaaaaaaaaaaaaaaaa' 这样的字符串并将其拆分为 4 个长度的元组，例如 (aaaa,aaaa,aaaa)

解决方案

使用 textwrap.wrap:

<预><代码>>>>导入文本换行>>>s = 'aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa>>>textwrap.wrap(s, 4)['aaaa', 'aaaa', 'aaaa', 'aaaa', 'aaaa', 'aaa']

How would I be able to take a string like 'aaaaaaaaaaaaaaaaaaaaaaa' and split it into 4 length tuples like (aaaa,aaaa,aaaa)

解决方案

Use textwrap.wrap:

>>> import textwrap
>>> s = 'aaaaaaaaaaaaaaaaaaaaaaa'
>>> textwrap.wrap(s, 4)
['aaaa', 'aaaa', 'aaaa', 'aaaa', 'aaaa', 'aaa']

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