在 1 行代码中打开读取和关闭文件 [英] open read and close a file in 1 line of code

问题描述

现在我使用:

pageHeadSectionFile = open('pagehead.section.htm','r')
output = pageHeadSectionFile.read()
pageHeadSectionFile.close()

但是为了让代码看起来更好，我可以这样做:

But to make the code look better, I can do:

output = open('pagehead.section.htm','r').read()

使用上述语法时，如何关闭文件以释放系统资源?

When using the above syntax, how do I close the file to free up system resources?

推荐答案

您实际上不必关闭它 - Python 会在垃圾收集期间或程序退出时自动执行此操作.但正如@delnan 指出的那样，出于各种原因明确关闭它是更好的做法.

You don't really have to close it - Python will do it automatically either during garbage collection or at program exit. But as @delnan noted, it's better practice to explicitly close it for various reasons.

那么，您可以做些什么来保持简短、简单和明确:

So, what you can do to keep it short, simple and explicit:

with open('pagehead.section.htm','r') as f:
    output = f.read()

我认为现在只有两行，而且可读性很强.

Now it's just two lines and pretty readable, I think.

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