计算字符串中的字母频率 (Python) [英] Counting Letter Frequency in a String (Python)

问题描述

我正在尝试计算单词中每个字母出现的次数

I am trying to count the occurrences of each letter of a word

word = input("Enter a word")

Alphabet=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

for i in range(0,26):
    print(word.count(Alphabet[i]))

当前输出每个字母出现的次数，包括没有出现的次数.

This currently outputs the number of times each letter occurs including the ones that don't.

如何垂直列出字母及其旁边的频率，例如，如下所示?

How do I list the letters vertically with the frequency alongside it, e.g., like the following?

word=你好"

H 1

E 1

L 2

O 1

推荐答案

from collections import Counter
counts=Counter(word) # Counter({'l': 2, 'H': 1, 'e': 1, 'o': 1})
for i in word:
    print(i,counts[i])

尝试使用 Counter，这将创建一个字典，其中包含集合中所有项目的频率.

Try using Counter, which will create a dictionary that contains the frequencies of all items in a collection.

否则，只有当 word.count(Alphabet[i]) 大于 0 时，您才可以对当前代码设置条件以print，尽管那将是较慢.

Otherwise, you could do a condition on your current code to print only if word.count(Alphabet[i]) is greater than 0, though that would be slower.

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