转换字符数组在C INT编号 [英] Convert char array to a int number in C

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问题描述

我想转换一个char []数组,如:

I want to convert a char array[] like:

char myarray[4] = {'-','1','2','3'}; //where the - means it is negative

因此​​,它应该是整数:-1234
使用标准çlibaries 。我找不到任何优雅的方式来做到这一点。

So it should be the integer: -1234 using standard libaries in C. I could not find any elegant way to do that.

我可以把'\\ 0'是肯定的。

I can append the '\0' for sure.

推荐答案

我个人不喜欢的atoi 功能。我建议的sscanf

I personally don't like atoi function. I would suggest sscanf:

char myarray[5] = {'-', '1', '2', '3', '\0'};
int i;
sscanf(myarray, "%d", &i);

这是非常标准的,它在 stdio.h中库:)

在我看来,它可以让你比更自由的atoi ,你的电话号码串的任意格式,而且很可能还允许非数字字符结尾

And in my opinion, it allows you much more freedom than atoi, arbitrary formatting of your number-string, and probably also allows for non-number characters at the end.

修改
我刚刚发现这个奇妙的<一个href=\"http://stackoverflow.com/questions/3420629/convert-string-to-integer-sscanf-or-atoi\">question这里的介绍并比较3种不同的方式来做到这一点的网站 - 的atoi 的sscanf strtol将。此外,还有一个很好的更详细的洞察的sscanf (实际上,全家 * scanf函数函数)。

EDIT I just found this wonderful question here on the site that explains and compares 3 different ways to do it - atoi, sscanf and strtol. Also, there is a nice more-detailed insight into sscanf (actually, the whole family of *scanf functions).

EDIT2
看起来它不只是我个人不喜欢的的atoi 功能。这里有一个链接一个答案解释说,的atoi 功能是德precated,不应该在新的code可以使用

EDIT2 Looks like it's not just me personally disliking the atoi function. Here's a link to an answer explaining that the atoi function is deprecated and should not be used in newer code.

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