在 Python TKinter 中创建弹出窗口时禁用底层窗口 [英] Disable the underlying window when a popup is created in Python TKinter

问题描述

我有一个主框架(称为a)和一个弹出式顶层(称为b).当 b 处于活动状态"时，如何确保用户无法点击 a 中的任何内容?

I have a master Frame (call it a), and a popup Toplevel (call it b). How do I make sure the user cannot click on anything in a while b is "alive"?

推荐答案

如果您不想隐藏根目录而只是确保用户只能与弹出窗口交互，则可以使用 grab_set() 和 grab_release().

If you don't want to hide the root but just make sure the user can only interact with the popup, you can use grab_set() and grab_release().

b.grab_set() # when you show the popup
# do stuff ...
b.grab_release() # to return to normal

或者，您可以withdraw()根使其不可见:

Alternatively, you could withdraw() the root to make it invisible:

a.withdraw()

将使根保持活动状态，但只有 b 可见.

will leave the root alive, but only b visible.

如果你需要它回来，你可以做

If you need it back, you can do

a.deiconify()

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