在对象中实现打包/解包 [英] Implement packing/unpacking in an object
问题描述
我有一个只包含属性的类,我想打包/解包来处理它.我应该实施什么 collections.abc
来获得这种行为?
I have a class that only contains attributes and I would like packing/unpacking to work on it. What collections.abc
should I implement to get this behaviour?
class Item(object):
def __init__(self, name, age, gender)
self.name = name
self.age = age
self.gender = gender
a, b, c = Item("Henry", 90, "male")
我想避免使用 namedtuple
.
推荐答案
您可以解压任何 可迭代
.这意味着您需要实现 __iter__
方法,并返回一个迭代器.在您的情况下,这可能只是:
You can unpack any Iterable
. This means you need to implement the __iter__
method, and return an iterator. In your case, this could simply be:
def __iter__(self):
return iter((self.name, self.age, self.gender))
或者,您可以将您的类设为 Iterator
,然后 __iter__
会 return self
并且你需要实现 __next__
;这是更多的工作,可能不值得付出努力.
Alternatively you could make your class an Iterator
, then __iter__
would return self
and you'd need to implement __next__
; this is more work, and probably not worth the effort.
有关详细信息,请参阅Python 的迭代器、可迭代和迭代协议究竟是什么?
根据我上面链接的问题,您还可以使用 __getitem__
实现迭代:
Per the question I linked above, you could also implement an iterable with __getitem__
:
def __getitem__(self, index):
return (self.name, self.age, self.gender)[index]
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