如何使用python运行带有参数的exe文件 [英] how to run an exe file with the arguments using python

问题描述

假设我有一个文件 RegressionSystem.exe.我想用 -config 参数执行这个可执行文件.命令行应该是这样的:

Suppose I have a file RegressionSystem.exe. I want to execute this executable with a -config argument. The commandline should be like:

RegressionSystem.exe -config filename

我尝试过:

regression_exe_path = os.path.join(get_path_for_regression,'Debug','RegressionSystem.exe')
config = os.path.join(get_path_for_regression,'config.ini')
subprocess.Popen(args=[regression_exe_path,'-config', config])

但是没有用.

推荐答案

您也可以使用 subprocess.call() 如果你愿意.例如，

You can also use subprocess.call() if you want. For example,

import subprocess
FNULL = open(os.devnull, 'w')    #use this if you want to suppress output to stdout from the subprocess
filename = "my_file.dat"
args = "RegressionSystem.exe -config " + filename
subprocess.call(args, stdout=FNULL, stderr=FNULL, shell=False)

call 和 Popen 的区别基本上是 call 是阻塞的，而 Popen 不是，用 Popen 提供更通用的功能.通常call 适用于大多数用途，它本质上是一种方便的Popen 形式.您可以在 这个问题.

The difference between call and Popen is basically that call is blocking while Popen is not, with Popen providing more general functionality. Usually call is fine for most purposes, it is essentially a convenient form of Popen. You can read more at this question.

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