正则表达式匹配 YAML 中的键 [英] Regex to match key in YAML

问题描述

我有一个看起来像这样的 yaml ..！用户可以定义N个xyz_flovor_id，其中_flovor_id键是通用的.目的是获取 *_flavor_id 键并从中提取值.

I have a yaml which looks like this..! User can define N number of xyz_flovor_id where _flovor_id key will be common. Aim is to grab *_flavor_id key and extract value out of it.

  server:
    tenant: "admin"
    availability_zone: "nova"
    cpu_overcommit_ratio: 1:1
    memory_overcommit_ratio: 1:1
    xyz_flovor_id: 1
    abc_flavor_id: 2

我能够计算出与 _flovor_id 匹配的正则表达式.然而，当试图在代码中使用它时，它会抛出错误.这是我的代码.

I am able to figure the regex to match the _flovor_id. however while trying to use this in code it's throwing Error. here is my code.

def get_flavor_keys(params):
    pattern = re.compile(r'[^*]flavor_id')
    for key, value in params.iteritems():
        print value
        if key == 'server':
            if pattern.match(value):
                print 'test'

print value 正在转储整个 YAML 文件(预期).之后立即回溯.

print value is dumping entire YAML file (expected). Immediate traceback after that.

Traceback (most recent call last):
  File "resource_meter.py", line 150, in <module>
    get_flavor_keys(items)
  File "resource_meter.py", line 15, in get_flavor_keys
    if pattern.match(value):
TypeError: expected string or buffer

推荐答案

您需要这个正则表达式.我将它分组为键值对:

You need this regex. I grouped it to key-value pair:

^\s*(?P<key>\w+_flavor_id):\s*(?P<value>\d+)

Python 演示:https://repl.it/Lk5W/0

import re

regex = r"^\s*(?P<key>\w+_flavor_id):\s*(?P<value>\d+)"

test_str = ("  server:\n"
    "    tenant: \"admin\"\n"
    "    availability_zone: \"nova\"\n"
    "    cpu_overcommit_ratio: 1:1\n"
    "    memory_overcommit_ratio: 1:1\n"
    "    xyz_flavor_id: 1\n"
    "    abc_flavor_id: 2\n")

matches = re.finditer(regex, test_str, re.MULTILINE)

for matchNum, match in enumerate(matches):
    print ("{key}:{value}".format(key = match.group('key'), value=match.group('value')))

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