在python 2.7中删除_之前和包括_的字符 [英] Remove characters before and including _ in python 2.7

问题描述

以下代码返回一个很好的可读输出.

def add_line_remove_special(ta_from,endstatus,*args,**kwargs):尝试:ta_to = ta_from.copyta(status=endstatus)infile = botslib.opendata(ta_from.filename,'r')tofile = botslib.opendata(str(ta_to.idta),'wb')开始 = infile.readline()导入文本换行行 = "\r\n".join(textwrap.wrap(start, 640))tofile.write(行)infile.close()tofile.close()

这是输出，现在我想删除所有字符，直到并包括 _

Ichg_UNBUNOA3 14 2090100000015 14 1304221445000001MSG_BGM380 610809 9 不适用MSG_DTM13720130422 102Grp1_RFFON 测试 EDIGrp2_NADBY 2090100000015 9Grp2_NADIV 2090100000015 9Grp2_NADDP 2090100000015 9Grp7_CUX2 EUR4Grp8_PAT22 5 3 D 30Grp25_LIN1 02090100000022 ENGrp25_QTY47 5Grp25_QTY12 5Grp26_MOA203 15.00Grp28_PRIINV 3000.00 1000PCEGrp33_TAX7 增值税 21.00 秒Grp25_LIN2 02090100000039 ENGrp25_QTY47 10Grp25_QTY12 10Grp26_MOA203 350.00Grp28_PRIINV 35000.00 1000PCEGrp33_TAX7 增值税 21.00 秒

我该怎么做?

解决方案

要获取下划线字符后一行的所有文本，在第一个 _ 字符处拆分并取结果的最后一个元素:

line.split('_', 1)[-1]

这也适用于没有在行上有下划线字符的行.

演示:

<预><代码>>>>'Grp25_QTY47 5'.split('_', 1)[-1]'QTY47 5'>>>'无下划线'.split('_', 1)[-1]'没有下划线'

将其转换为您的代码:

导入文本换行ta_to = ta_from.copyta(status=endstatus)使用 botslib.opendata(ta_from.filename,'r') 作为 infile:使用 botslib.opendata(str(ta_to.idta),'wb') 作为 tofile:对于 textwrap.wrap(next(infile), 640) 中的行:line = line.split('_', 1)[-1]tofile.write(line + '\r\n')

The following code returns into a nice readable output.

def add_line_remove_special(ta_from,endstatus,*args,**kwargs):
    try:
        ta_to = ta_from.copyta(status=endstatus)
        infile = botslib.opendata(ta_from.filename,'r')
        tofile = botslib.opendata(str(ta_to.idta),'wb')
        start = infile.readline()
        import textwrap
        lines= "\r\n".join(textwrap.wrap(start, 640))
        tofile.write(lines)
        infile.close()
        tofile.close()

This is the output, now I would like to remove all the characters until and including the _

Ichg_UNBUNOA3                                   14                2090100000015                      14                1304221445000001
MSG_BGM380                                         610809                             9  NA
MSG_DTM13720130422                           102
Grp1_RFFON test EDI
Grp2_NADBY 2090100000015                         9
Grp2_NADIV 2090100000015                         9
Grp2_NADDP 2090100000015                         9
Grp7_CUX2  EUR4
Grp8_PAT22                                                                                              5  3  D   30
Grp25_LIN1        02090100000022                     EN
Grp25_QTY47               5
Grp25_QTY12               5
Grp26_MOA203             15.00
Grp28_PRIINV        3000.00           1000PCE
Grp33_TAX7  VAT                                                                                 21.00                              S
Grp25_LIN2        02090100000039                     EN
Grp25_QTY47              10
Grp25_QTY12              10
Grp26_MOA203            350.00
Grp28_PRIINV       35000.00           1000PCE
Grp33_TAX7  VAT                                                                                 21.00                              S

How can I do this?

解决方案

To get all text on a line after a underscore character, split on the first _ character and take the last element of the result:

line.split('_', 1)[-1]

This will also work for lines that do not have an underscore character on the line.

Demo:

>>> 'Grp25_QTY47               5'.split('_', 1)[-1]
'QTY47               5'
>>> 'No underscore'.split('_', 1)[-1]
'No underscore'

Translating this to your code:

import textwrap

ta_to = ta_from.copyta(status=endstatus)
with botslib.opendata(ta_from.filename,'r') as infile:
    with botslib.opendata(str(ta_to.idta),'wb') as tofile:
        for line in textwrap.wrap(next(infile), 640):
            line = line.split('_', 1)[-1]
            tofile.write(line + '\r\n')

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