提取特定字符后的文本 [英] Extract text after specific character

问题描述

我需要提取@

后面的单词

我该怎么做?我正在尝试:

text="你好@bob ！"user=text[text.find("@")+1:]打印用户

输出:

鲍勃！

但正确的输出应该是:

鲍勃

解决方案

一个有趣的正则表达式解决方案:

<预><代码>>>>进口重新>>>re.findall(r'@(\w+)', '@Hello there @bob @!')['你好'，'鲍勃']>>>re.findall(r'@(\w+)', '你好，鲍勃！')[]>>>(re.findall(r'@(\w+)', 'Hello there @bob !') 或 None,)[0]'鲍勃'>>>打印 (re.findall(r'@(\w+)', 'Hello there bob !') 或 None,)[0]没有任何

上面的正则表达式将选取一个或多个字母数字字符的模式，直到找到一个非字母数字字符.

如果您想捕获更广泛的子字符串，这里有一个匹配一个或多个非空白字符的正则表达式解决方案:

<预><代码>>>>re.findall(r'@(\S+?)', '@Hello there @bob @!')['你好'，'鲍勃'，'！']

请注意，当上面的正则表达式遇到像 @xyz@abc 这样的字符串时，它会在一个结果中捕获 xyz@abc 而不是 xyz和 abc 分开.为了解决这个问题，你可以使用否定的 \s 字符类，同时也否定 @ 字符:

<预><代码>>>>re.findall(r'@([^\s@]+)', '@xyz@abc 一些其他的东西')['xyz', 'abc']

这里有一个正则表达式解决方案，用于匹配一个或多个字母字符，以防万一您不想要任何数字或其他任何东西:

<预><代码>>>>re.findall(r'@([A-Za-z]+)', '@你好@bobv2.0 @!')['你好', 'bobv']

I need to extract the word after the @

How can I do that? What I am trying:

text="Hello there @bob !"
user=text[text.find("@")+1:]
print user

output:

bob !

But the correct output should be:

bob

解决方案

A regex solution for fun:

>>> import re
>>> re.findall(r'@(\w+)', '@Hello there @bob @!')
['Hello', 'bob']
>>> re.findall(r'@(\w+)', 'Hello there bob !')
[]
>>> (re.findall(r'@(\w+)', 'Hello there @bob !') or None,)[0]
'bob'
>>> print (re.findall(r'@(\w+)', 'Hello there bob !') or None,)[0]
None

The regex above will pick up patterns of one or more alphanumeric characters following an '@' character until a non-alphanumeric character is found.

Here's a regex solution to match one or more non-whitespace characters if you want to capture a broader range of substrings:

>>> re.findall(r'@(\S+?)', '@Hello there @bob @!')
['Hello', 'bob', '!']

Note that when the above regex encounters a string like @xyz@abc it will capture xyz@abc in one result instead of xyz and abc separately. To fix that, you can use the negated \s character class while also negating @ characters:

>>> re.findall(r'@([^\s@]+)', '@xyz@abc some other stuff')
['xyz', 'abc']

And here's a regex solution to match one or more alphabet characters only in case you don't want any numbers or anything else:

>>> re.findall(r'@([A-Za-z]+)', '@Hello there @bobv2.0 @!')
['Hello', 'bobv']

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