计算文件中的特定字符(Python) [英] Counting specific characters in a file (Python)

问题描述

我想计算文件中的特定内容，即 "--undefined--" 出现的次数.这是文件的一部分内容:

I'd like to count specific things from a file, i.e. how many times "--undefined--" appears. Here is a piece of the file's content:

"jo:ns  76.434
pRE     75.417
zi:     75.178
dEnt    --undefined--
ba      --undefined--

我尝试使用这样的东西.但它不起作用:

I tried to use something like this. But it won't work:

with open("v3.txt", 'r') as infile:
    data = infile.readlines().decode("UTF-8")

    count = 0
    for i in data:
        if i.endswith("--undefined--"):
            count += 1
    print count

我是否必须实现元组字典来解决这个问题，或者有更简单的解决方案吗?

Do I have to implement, say, dictionary of tuples to tackle this or there is an easier solution for that?

有问题的单词在一行中只出现一次.

The word in question appears only once in a line.

推荐答案

readlines() 返回行列表，但它们没有被剥离(即它们包含换行符).要么先剥离它们:

readlines() returns the list of lines, but they are not stripped (ie. they contain the newline character). Either strip them first:

data = [line.strip() for line in data]

或检查 --undefined--\n:

if line.endswith("--undefined--\n"):

或者，考虑字符串的 .count() 方法:

Alternatively, consider string's .count() method:

file_contents.count("--undefined--")

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