解压后无法删除压缩文件 [英] Unable to remove zipped file after unzipping

问题描述

在 Windows 上解压缩内容后，我试图删除压缩文件.内容可以存储在 zip 的文件夹结构中.我正在使用 with 语句，并认为这会关闭类文件对象 (source var) 和 zip 文件.我删除了与保存源文件相关的代码行.

I'm attempting to remove a zipped file after unzipping the contents on windows. The contents can be stored in a folder structure in the zip. I'm using the with statement and thought this would close the file-like object (source var) and zip file. I've removed lines of code relating to saving the source file.

import zipfile
import os

zipped_file = r'D:\test.zip'

with zipfile.ZipFile(zipped_file) as zip_file:
    for member in zip_file.namelist():
        filename = os.path.basename(member)
        if not filename:
            continue
        source = zip_file.open(member)

os.remove(zipped_file)

返回的错误是:

WindowsError: [Error 32] The process cannot access the file because it is being used by another process: 'D:\\test.zip'

我试过了:

• 循环遍历 os.remove 行，以防出现轻微的计时问题
• 显式使用 close 而不是 with 语句
• 尝试在本地 C 盘和映射 D 盘

• looping over the os.remove line in case it's a slight timing issue
• Using close explicitly instead of the with statment
• Attempted on local C drive and mapped D Drive

推荐答案

不是将字符串传递给 ZipFile 构造函数，您可以将它传递给类似对象的文件:

instead of passing in a string to the ZipFile constructor, you can pass it a file like object:

import zipfile
import os

zipped_file = r'D:\test.zip'

with open(zipped_file, mode="r") as file:
    zip_file = zipfile.ZipFile(file)
    for member in zip_file.namelist():
        filename = os.path.basename(member)
        if not filename:
            continue
        source = zip_file.open(member)

os.remove(zipped_file)

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