python2中的python3 datetime.timestamp? [英] python3 datetime.timestamp in python2?
问题描述
我有一段 python3 代码,它在 22:00 调用一个函数.
I have a piece of python3 code, that calls a function at 22:00.
# Imports
from datetime import datetime, date, time, timedelta
import sched
import time as mod_time
# Find the next datetime corresponding to 22:00
first_run = datetime.combine(date.today(), time(22,0))
first_run = first_run if first_run > datetime.now() else first_run + timedelta(1)
# Dumb test function
def my_function():
print('my_function')
# Run the function at 22:00
scheduler = sched.scheduler(mod_time.time, mod_time.sleep)
scheduler.enterabs(first_run.timestamp(), 1, my_function, ())
scheduler.run()
此代码目前在 python3 中运行.我希望它在 python2 中工作.我唯一的问题来自以下几点:
This code is currently working in python3. I would like it to work in python2. My only problem comes from the following:
first_run.timestamp()
我尝试用以下内容替换它:
I tried to replace it with something like:
(first_run - datetime(1970, 1, 1)).total_seconds()
但我的时区似乎有问题(UTC 太容易了,我在 UTC+2).first_run 中应该有一些与 tzinfo 相关的东西.也许我应该添加一些东西?
But there seems to be a problem with my timezone (UTC would be too easy, I'm in UTC+2). There should be something with tzinfo in first_run. Maybe I should add something?
我很迷茫,任何帮助将不胜感激.非常感谢您帮助我.
I'm quite lost, and any help would be appreciated. Thanks a lot by advance for helping me.
编辑 1:
在 Haochen Wu 的评论之后,我阅读了 将日期时间转换为 Unix 时间戳并在 python 中将其转换回
After Haochen Wu's comment, I've read Convert datetime to Unix timestamp and convert it back in python
现在我知道以下几行对我来说是等效的:
Now I know that the following lines are equivalent for me:
(datetime.now() - datetime(1970, 1, 1)).total_seconds()
(datetime.now() - datetime.utcfromtimestamp(0)).total_seconds()
解决方案应该是
(datetime.now() - datetime.fromtimestamp(0)).total_seconds()
但事实并非如此.这个值仍然与mod_time.time()
不同.
But this is not the case. This value is still different from mod_time.time()
.
也许是因为冬天/夏天的时间?
Maybe because of winter/summer hours?
推荐答案
在python 2中使用以下方法转换为时间戳
use the following to convert to a timestamp in python 2
int((mod_time.mktime(first_run.timetuple())+first_run.microsecond/1000000.0))
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