python input() EOF 错误和 int 类型的返回值? [英] python input() EOF error and return value of type int?

问题描述

关于这 2 个短代码，我有 2 个问题.

I have 2 questions on these 2 short codes.

1.

name = input('what: ')
print(name)

输出

what: 641u
Traceback (most recent call last):
  File "/Users/vuthynun/PycharmProjects/untitled1/h/__init__.py", line 1, in <module>
    name = input('what: ')
  File "<string>", line 1
    641u
       ^
SyntaxError: unexpected EOF while parsing

Process finished with exit code 1

为什么它给我这个错误?

Why does it give me this error?

2.

name = input('what: ')

print(type(name))

输出:

what: 23
<type 'int'>

Process finished with exit code 0

为什么名字类型是int?我以为所有输入都转换为字符串.

Why is name type int? I thought all input are converted to string.

请帮助我理解这一点.害死我了.

Please please please help me understand this. It's killing me.

推荐答案

在 python 2 中使用 raw_input 而不是 input.这就是你获得字符串的方式.否则python会评估你给它的东西，这会给你意想不到的行为.

Use raw_input instead of input in python 2. That's how you get strings. Otherwise python will evaluate what you give it, which is giving you your unexpected behaviour.

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