从最接近给定元素的值的向量返回索引 [英] return index from a vector of the value closest to a given element

问题描述

我有一个元素列表，例如

I have a list of elements such as

A=
  0.992688
  0.892195
  0.889151
  0.380672
  0.180576
  0.685028
  0.58195

给定一个输入元素，比如 0.4，我如何找到最接近这个数字的索引.例如，A[4] = 0.380672 最接近 0.4.所以应该回到4

Given an input element, like 0.4, how can I find the index that holds the number being most near to this number. For instance, A[4] = 0.380672 is most near to 0.4. Therefore, it should return to 4

推荐答案

一种方式:

# as mnel points out in his answer, the difference,
# using `which` here gives all indices that match
which(abs(x-0.4) == min(abs(x-0.4)))

其中 x 是您的向量.

或者，

# this one returns the first index, but is SLOW
sort(abs(x-0.4), index.return=T)$ix[1]

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