用因子替换范围内的数字 [英] Replacing numbers within a range with a factor
本文介绍了用因子替换范围内的数字的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
给定一个数据框列,它是一系列整数(年龄),我想将整数范围转换为序数变量.
Given a dataframe column which is a series of integers (age), I want to convert ranges of integers into ordinal variables.
我当前的代码不起作用,我该怎么做?
My current code doesn't work, how do I do this?
df <- read.table("http://dl.dropbox.com/u/822467/df.csv", header = TRUE, sep = ",")
df[(df >= 0) & (df <= 14)] <- "Age1"
df[(df >= 15) & (df <= 44)] <- "Age2"
df[(df >= 45) & (df <= 64)] <- "Age3"
df[(df > 64)] <- "Age4"
table(df)
推荐答案
使用cut
一步完成:
dfc <- cut(df$x, breaks=c(0, 15, 45, 56, Inf))
str(dfc)
Factor w/ 4 levels "(0,15]","(15,45]",..: 3 4 3 2 2 4 2 2 4 4 ...
一旦您对 breaks
的正确指定感到满意,您还可以使用 labels
参数来重新标记级别:
Once you are satisfied that the breaks
are correctly specified, you can then also use the labels
argument to relabel the levels:
dfc <- cut(df$x, breaks=c(0, 15, 45, 56, Inf), labels=paste("Age", 1:4, sep=""))
str(dfc)
Factor w/ 4 levels "Age1","Age2",..: 3 4 3 2 2 4 2 2 4 4 ...
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