Python 有模拟 C 的 rand() 序列的函数吗? [英] Does Python have a function to mimic the sequence of C's rand()?

问题描述

我正在寻找一个 Python 函数，它可以在 c 中模拟 rand()(和 srand())的行为，并满足以下要求:

I am looking for a Python function that will mimic the behavior of rand() (and srand()) in c with the following requirements:

1. 我可以在与 srand() 等价的 Python 中提供相同的纪元时间来为函数提供种子
2. 等价的 rand()%256 应该产生与 c 中相同的 char 值，如果两者都提供相同的种子.

到目前为止，我已经考虑了随机库和 numpy 的随机库.而不是像 C 那样提供从 0 到 32767 的随机数，尽管两者都在其随机函数上产生从 0 到 1 的浮点数.在尝试 random.randint(0,32767) 时，我产生了与在 C 函数中不同的结果.

So far, I have considered both the random library and numpy's random library. Instead of providing a random number from 0 to 32767 as C does though both yield a floating point number from 0 to 1 on their random functions. When attempting random.randint(0,32767), I yielded different results than when in my C function.

TL;博士Python 中是否存在遵循与 C 相同的随机序列的现有函数/库?

TL;DR Is there an existing function/libary in Python that follows the same random sequence as C?

推荐答案

您可以使用 random.seed().以下示例每次运行时都应打印相同的序列:

You can use random.seed(). The following example should print the same sequence every time it runs:

import random
random.seed(42)
for _ in range(10):
    print(random.randint(0, 32768))

更新:刚刚看到 OP 的最后一条评论.不，由于其他注释中给出的原因，此代码不会为您提供与 C 代码相同的序列.两种不同的 C 实现也不会一致.

Update: Just saw the last comment by the OP. No, this code won't give you the same sequence as the C code, because of reasons given in other comments. Two different C implementations won't agree either.

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