如何构建 Apache Commons Lang Range<Integer>目的? [英] How to construct an Apache Commons Lang Range&lt;Integer&gt; object?

问题描述

如何创建 Apache Commons Lang 3.1 Range 对象?

JavaDocs 说:

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从最小到最大点的不可变对象范围."

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"对象要么是 Comparable 的实现，要么您需要提供一个 Comparator."

但是当我尝试时:

范围<整数>range = new Range(100, 200);

我的 IDE 中出现错误，提示所需参数为整数、整数、比较器.

即使 Integer 实现了 Comparable 接口，因此我不需要额外的比较器.

谁能举一个例子来说明如何构造上述Range对象?

解决方案

Range 的构造函数似乎是私有的，因此静态方法可能是构造对象的首选方式.

例如，您似乎可以使用静态方法 between 来构造范围:

Range.between(100, 200);

但是还有其他静态方法，这取决于您的需要.

How can I create a Apache Commons Lang 3.1 Range<Inreger> object?

The JavaDocs say:

"An immutable range of objects from a minimum to maximum point inclusive."

"The objects need to either be implementations of Comparable or you need to supply a Comparator."

But when I try:

Range<Integer> range = new Range<Integer>(100, 200);

I get an error in my IDE that says required arguments are Integer, Integer, comparator.

Even though Integer implements the Comparable interface and thus I shouldn't need a extra comparator.

Can someone give me an example of how to construct the above described Range<Integer> object?

解决方案

The constructor of Range appears to be private so a static method may be the preferred way of constructing the object.

For example, it looks like you could use the static method between to construct a Range:

Range.between(100, 200);

However there are other static methods, it just depends what you need.

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