使用给定的步数获取给定最小值和最大值的可枚举范围 [英] Get an enumerable range for a given min and max with a given number of steps

问题描述

我熟悉 枚举.Range 方法用于生成值的枚举.但我想要一些稍微不同的东西.我想提供最小值、最大值和所需的点数.

I am familiar with the Enumerable.Range method for generating an enumeration of values. But I would like something slightly different. I want to provide a min value, max value, and a number of desired points.

IE:

Method(double min, double max, int numberOfSteps)

采取

方法(0, 1000, 11);

会回来

0, 100, 200, 300, 400, 500, 600, 700, 800, 900, 1000

我想像这样的东西，一定有一个内置的方法，但我的搜索没有找到任何东西.我错过了什么吗?

I figure for something like this, there must be a built-in method but my search hasn't turned anything up. Am I missing something?

推荐答案

除了您希望值是 double 之外，其他一切都可以使用 Enumerable.Range.我不认为有任何内置的东西可以做你想做的事，但在 Enumerable.Range 之上实现是微不足道的:

Other than the fact that you want the values to be double, everything else can be done with Enumerable.Range. I don't think there's anything built-in to do what you want, but it's trivial to implement on top of Enumerable.Range:

return Enumerable.Range(0, steps)
                 .Select(i => min + (max - min) * ((double)i / (steps - 1)));

我写得有点仔细，所以你总是得到最终的价值.如果你说你只想要一个步骤，它确实很无聊......你可能想要防止这种情况并在这种情况下使用 Enumerable.Repeat(min, 1) .

I've written that somewhat carefully so that you always end up with the final value. It does bork if you say you only want a single step though... you might want to guard against that and use Enumerable.Repeat(min, 1) in that case.

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