xslt 根据在另一个节点树中引用的属性获取元素值 [英] xslt get element value based on attribute which is referenced in another node tree
问题描述
我有以下 xml 文件:
I have the following xml file:
<?xml version="1.0" encoding="utf-8" ?>
<root>
<rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:skosxl="http://www.w3.org/2008/05/skos-xl#"
xmlns:skos="http://www.w3.org/2004/02/skos/core#"
xmlns:dc="http://purl.org/dc/terms/"
xmlns:ns0="http://art.uniroma2.it/ontologies/vocbench#"
xmlns:void="http://rdfs.org/ns/void#">
<skos:Concept rdf:about="http://aims.fao.org/aos/agrovoc/c_26321">
<skos:prefLabel xml:lang="fa">آبیس ماریزیای</skos:prefLabel>
....
<skos:prefLabel xml:lang="en">Abies mariesii</skos:prefLabel>
....
<skos:broader rdf:resource="http://aims.fao.org/aos/agrovoc/c_10"/>
</skos:Concept>
<skos:Concept rdf:about="http://aims.fao.org/skosmos/agrovoc/en/page/c_1591">
<skos:prefLabel xml:lang="ar">أشجار عيد الميلاد</skos:prefLabel>
....
<skos:prefLabel xml:lang="en">christmas trees</skos:prefLabel>
....
</skos:Concept>
....
<skos:Concept>
<ns0:isUsedAs rdf:resource="http://aims.fao.org/skosmos/agrovoc/en/page/c_7776"/>
<ns0:isUsedAs rdf:resource="http://aims.fao.org/skosmos/agrovoc/en/page/c_1591"/>
</skos:Concept>
</rdf:RDF>
</root>
我想获得 <skos:prefLabel xml:lang="en"> 的值，它有一个父 skos:Concept 和这个 skos:Concept 在另一个节点树 ns0:isUsedAs 中被引用.因此，我们得到 'christmas tree' 的值 ns0:isUsedAs rdf:resource="http://aims.fao.org/skosmos/agrovoc/en/page/c_1591.我想将其输出为文本，如下所示:
I want to get the value of <skos:prefLabel xml:lang="en"> which has a parent skos:Concept and this skos:Concept is referenced in another node tree ns0:isUsedAs. Thus, we get the value of 'christmas tree' for ns0:isUsedAs rdf:resource="http://aims.fao.org/skosmos/agrovoc/en/page/c_1591. And I want to output this as text, same as below:
=305 \\$aisUsedAs$bchristmas tree
请注意 skos:prefLabel 是 skos:Concept 的子项.ns0:isUsedas 也是 skos:Concept 的子节点，但位于另一个节点树中.我也已经有了以下初步的 xsl:templates:
Please take note that skos:prefLabel is a child of skos:Concept. ns0:isUsedas is a also child of skos:Concept, but is in another node tree.
I also already have the following preliminary xsl:templates:
<xsl:template match="root">
<xsl:for-each select="rdf:RDF">
<xsl:text>START HERE</xsl:text>
<xsl:text> </xsl:text>
<xsl:text>=LDR 00000nam 2200000Ia 4500</xsl:text>
<xsl:text> </xsl:text>
<xsl:apply-templates select="rdf:Description/skos:narrowMatch" />
<xsl:text> </xsl:text>
<xsl:apply-templates select="rdf:Description/skos:exactMatch" />
<xsl:text> </xsl:text>
<xsl:apply-templates select="skos:Concept" />
<xsl:text> </xsl:text>
<xsl:apply-templates select="skos:Concept/skos:altLabel" />
<xsl:text> </xsl:text>
<xsl:apply-templates select="skos:Concept/skos:prefLabel" />
<xsl:text> </xsl:text>
</xsl:for-each>
</xsl:template>
我希望你能帮助我解决我的问题.提前致谢！
I hope you can help me with my problem. Thanks in advance!
进一步更新:
这是一个基于 Dan 的回答的 xslt，但我仍然得到空白:
Here is an xslt based from Dan's answer, but I'm still getting blanks:
<xsl:transform
......
>
<xsl:template match="root">
<xsl:for-each select="rdf:RDF">
<xsl:text>START HERE</xsl:text>
<xsl:text> </xsl:text>
<xsl:text>=LDR 00000nam 2200000Ia 4500</xsl:text>
<xsl:text> </xsl:text>
<xsl:apply-templates select="rdf:Description/skos:narrowMatch" />
<xsl:text> </xsl:text>
<xsl:apply-templates select="rdf:Description/skos:exactMatch" />
<xsl:text> </xsl:text>
<xsl:apply-templates select="skos:Concept" />
<xsl:text> </xsl:text>
<xsl:apply-templates select="skos:Concept/skos:altLabel" />
<xsl:text> </xsl:text>
<xsl:apply-templates select="skos:Concept/skos:prefLabel" />
<xsl:text> </xsl:text>
</xsl:for-each>
</xsl:template>
<xsl:output method="text" omit-xml-declaration="yes" encoding="UTF-8" indent="no" />
<xsl:key name="concepts-by-about" match="//skos:Concept" use="@rdf:about" />
<xsl:template match="//ns0:isUsedAs[key('concepts-by-about', @rdf:resource)]">
=305 \\$aisUsedBy$b<xsl:value-of select="key('concepts-by-about', @rdf:resource)/skos:prefLabel[@xml:lang='en']" />
</xsl:template>
<xsl:template match="text()" />
</xsl:transform>
推荐答案
这应该会让你开始:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"
xmlns:skos="http://www.w3.org/2004/02/skos/core#"
xmlns:ns0="http://art.uniroma2.it/ontologies/vocbench#"
>
<xsl:template match="/">
<xsl:for-each select="//skos:Concept/ns0:isUsedAs/@rdf:resource">
<xsl:variable name='resource' select="."/>
<xsl:value-of select="//skos:Concept[@rdf:about=$resource]/skos:prefLabel[@xml:lang='en']"/>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
这篇关于xslt 根据在另一个节点树中引用的属性获取元素值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
