我怎么能烧焦以相反的顺序排列? [英] How can I char array in reverse order?
问题描述
我分配的问题是这样的。
编写一个程序,用它打印在字符数组中倒序字母
无效printReverse(字符字母[],INT大小);
例如,如果阵列包含{'C','s'的,'C','2','6','1'}的输出应为162csc
我继电器试图解决,但我不明白这是什么意思!
无效printReverse(字符字母[],INT大小);
所以我需要帮助乌拉圭回合知道我必须做的这出...
THX的家伙,我不喜欢这个,但那里调用方法printReverse到主法的问题!!
进口java.util.Arrays中;
进口java.util.Collections中;公共类搜索{公共静态无效的主要(字串[] args){的char [] =字母{'E','V','O','L','4'};
printReverse();}公共无效printReverse(的char []信函,INT大小){的for(int i = letters.length-1; I> = 0; I - ){
System.out.print(字母[I]);
}
}}
我相信你写的是你要创建的方法的签名。
公共无效printReverse(的char []信函,INT大小){
// code在这里
}
您将不得不遍历数组并打印它包含什么倒退。使用反向循环要经过的每个项目中的信。我会告诉你这些结合自己因为它是一个任务。下面是一个for循环的例子:
的for(int i = array.length-1; I> = 0; I - ){
System.out.print(数组[我]);
}
my assignment question is like that
Write a program which prints the letters in a char array in reverse order using
void printReverse(char letters[], int size);
For example, if the array contains {'c', 's', 'c', '2', '6', '1'} the output should be "162csc".
I relay tried to solve it but I don't understand what this means !! void printReverse(char letters[], int size);
so I need ur help to know what I have to do to figure this out ...
thx guys , I did like this but there's problem with calling the method "printReverse" into main method !!..
import java.util.Arrays;
import java.util.Collections;
public class search {
public static void main(String[] args) {
char[] letters = {'e', 'v', 'o', 'l', '4'};
printReverse();
}
public void printReverse(char[] letters, int size){
for (int i = letters.length-1; i >= 0 ; i--){
System.out.print(letters[i]);
}
}
}
I believe what you wrote is the signature of the method you have to create.
public void printReverse(char[] letters, int size){
//code here
}
You would have to iterate the array and print what it contains backwards. Use a reverse "for loop" to go through each item in "letters". I'll let you combine these yourself as it's an assignment. Here's an example of a for loop:
for (int i = array.length-1; i >= 0 ; i--){
System.out.print(array[i]);
}
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