如何将对象数组操作为不同的键和值? [英] How to manipulate an array of object into a different key and value?

问题描述

所以我有这个数组:

 [{date: "5/7/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},]

如何把数组变成:

[ {"5/6/2021" : 3}, // 3 because there are 3 data with 5/6/2021 date
  {"5/7/2021" : 1}] // 1 because there are 1 data with 5/7/2021 date

我的进步.updatedSales 是数组名称(编辑)

My Progress. updatedSales is the array name (Edit)

const temp = updatedSales.reduce((acc, { name, date }) => {
        acc[name] = acc[name] || { name, dates: new Set(), totalSubmit: 0 };
        acc[name].totalSubmit++;
        acc[name].dates.add(date);
        return acc;
    }, {});

    const result = Object.values(temp).map(({ name, dates, totalSubmit }) => ({ name, uniqueDate: dates.size, totalSubmit }));

 const updatedSales=[{date: "5/7/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},]

const temp = updatedSales.reduce((acc, { name, date }) => {
        acc[name] = acc[name] || { name, dates: new Set(), totalSubmit: 0 };
        acc[name].totalSubmit++;
        acc[name].dates.add(date);
        return acc;
    }, {});

    const result = Object.values(temp).map(({ name, dates, totalSubmit }) => ({ name, uniqueDate: dates.size, totalSubmit }));
    
console.log(result)

预期:

[ {"5/6/2021" : 3}, // 3 because there are 3 data with 5/6/2021 date
  {"5/7/2021" : 1}]

现在:

[{name: "bob", uniqueDate: 3, totalSubmit: 36},
 {name: "steve", uniqueDate: 12, totalSubmit: 116}]

我想要的输出是不同的日期，而不是名称.所以它就像5/6/2021"而不是鲍勃".

My desired output is the date to be different, not name. So its like "5/6/2021" instead of "bob".

推荐答案

只需对您的脚本稍加改动，您就会得到:

With just a few touches to your script you will get this:

const updatedSales=[{date: "5/7/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},
 {date: "5/6/2021", name: "bob"},]

const temp = updatedSales.reduce((acc, { name, date }) => {
        acc[date] = acc[date] || { date, dates: new Set(), totalSubmit: 0 };
        acc[date].totalSubmit++;
        acc[date].dates.add(date);
        return acc;
    }, {});

    const result = Object.values(temp).map(({ date, dates, totalSubmit }) => ( {[date]: totalSubmit }) );
    
console.log(result)

或者，如果您真的愿意，可以将其缩减为单行":

Or, if you really want to, you can reduce it down to a "one-liner":

const result = Object.entries(
    updatedSales.reduce((a,{date}) => {
      a[date] = (a[date] || 0) + 1;
      return a;  
    }, {})   ).map(([k,v])=> ( {[k]:v }) );

new Set() 在这里并不是真正需要的.

The new Set() is not really required here.

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