添加整数的NSMutableArray [英] Adding Integer To NSMutableArray
问题描述
我找不到任何地方这样,所以我要求只是要求,以确保。是的,我知道它的基本的,但我想我宁愿得到权利之前,我犯错误了一百万次:
如果我这样做,不是在默认情况下投出0,以一个NSNumber(如果没有,什么对象类型的话),或者我会做第二次code?
(或两种可能是错误的,我想要做的事。如果是这样,让我知道,他们都编译,所以我只是想知道哪一个是正确的(或preferred),为什么。)
code 1:
的NSMutableArray数组= [[[NSMutableArray里的alloc]初始化]自动释放];
[阵列ADDOBJECT:0];
code 2:
的NSMutableArray数组= [[[NSMutableArray里的alloc]初始化]自动释放];
[阵列ADDOBJECT:[NSNumber的numberWithInt:0]];
的NSMutableArray
的不采取原始类型的。
第二个选项是正确的。
块引用>I couldn't find this anywhere, so I am asking just asking to make sure. And yes, I know its basic, but I figure I'd rather get that right before I make the mistake a million times:
If I do the following, does it cast the "0" to an NSNumber by default (if not, what Object type is it), or would I have to do the 2nd code?
(Or both of these could be wrong for what I'm trying to do. If so, let me know. They both compile so I am just wondering which one is "right" (or preferred) and why.)
Code 1:
NSMutableArray array = [[[NSMutableArray alloc] init] autorelease]; [array addObject: 0];
Code 2:
NSMutableArray array = [[[NSMutableArray alloc] init] autorelease]; [array addObject: [NSNumber numberWithInt: 0]];
解决方案
NSMutableArray
doesn't take primitive types.The second option is correct.
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