Mono.Cecil - 如何获取方法体的简单示例 [英] Mono.Cecil - simple example how to get method body

问题描述

我一直在寻找一个新手问题，但找不到一个简单的例子.谁能给我一个简单的例子，如何将 MethodBody 放入最可用的字符串结果中?喜欢:

I have been searching for a newbie question, but can't find a simple example. Can anyone give me a simple example how to get MethodBody into most available string result? Like:

using Mono.Cecil;
using Mono.Cecil.Cil;

namespace my
{
    public class Main
    {
        public Main()
        {
             // phseudo code, but doesnt work
            Console.Write(    getMethod("HelloWorld").GetMethodBody().ToString()   );
        }

        public void HelloWorld(){
             MessageBox.Show("Hiiiiiiiiii");
        }
    }
}

推荐答案

从阅读你的程序集开始:

Start with reading your assembly:

var path = "... path to your assembly ...";
var assembly = AssemblyDefinition.ReadAssembly(path);

如果你想打开正在运行的进程，你可以使用System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName作为path

You can use System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName as path if you want to open running process

现在获取您想要检查的所有类型和方法

Now get all types and methods wich you want to inspect

var toInspect = assembly.MainModule
  .GetTypes()
  .SelectMany(t => t.Methods
      .Where(m => m.HasBody)
      .Select(m => new {t, m}))
  

如果您已经知道类型和方法名称，您可以像这样修改您的查询:

If you already knew type and method names you can modify your query something like this:

toInspect = toInspect.Where(x => x.t.Name.EndsWith("Main") && x.m.Name == "HelloWorld");

之后只需遍历该集合:

foreach (var method in toInspect)
{
    Console.WriteLine($"\tType = {method.t.Name}\n\t\tMethod = {method.m.Name}");
    foreach (var instruction in method.m.Body.Instructions)
        Console.WriteLine($"{instruction.OpCode} \"{instruction.Operand}\"");
}

输出将是

Type = Main
  Method = HelloWorld

ldstr "Hiiiiiiiiii"
call "System.Windows.Forms.DialogResult System.Windows.Forms.MessageBox::Show(System.String)"
pop ""
ret ""

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