RegEx:在引号之间抓取值 [英] RegEx: Grabbing values between quotation marks

问题描述

我有一个这样的值:

"Foo Bar" "Another Value" something else

什么正则表达式会返回用引号括起来的值(例如 Foo Bar 和 Another Value)?

What regex will return the values enclosed in the quotation marks (e.g. Foo Bar and Another Value)?

推荐答案

我一直在使用以下方法并取得了巨大的成功:

I've been using the following with great success:

(["'])(?:(?=(\\?))\2.)*?\1

它还支持嵌套引号.

对于那些想要更深入地解释其工作原理的人，以下是用户 ephemient 的解释:

For those who want a deeper explanation of how this works, here's an explanation from user ephemient:

([""']) 匹配一个引号；((?=(\\?))\2.) 如果反斜杠存在，吞噬它，无论是否发生，匹配一个字符；*? 匹配多次(非贪婪，以免吃掉结束语)；\1 匹配用于打开的同一个引号.

([""']) match a quote; ((?=(\\?))\2.) if backslash exists, gobble it, and whether or not that happens, match a character; *? match many times (non-greedily, as to not eat the closing quote); \1 match the same quote that was use for opening.

这篇关于RegEx:在引号之间抓取值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！