字符串的正则表达式不以给定后缀结尾 [英] Regex for string not ending with given suffix

问题描述

我找不到合适的正则表达式来匹配任何以某种条件结尾的not字符串.例如，我不想匹配任何以 a 结尾的内容.

I have not been able to find a proper regex to match any string not ending with some condition. For example, I don't want to match anything ending with an a.

匹配

b
ab
1

这不匹配

a
ba

我知道正则表达式应该以 $ 结尾来标记结束，但我不知道它前面应该有什么.

I know the regex should be ending with $ to mark the end, though I don't know what should preceed it.

编辑:原始问题似乎不是我的案例的合法示例.那么:如何处理多个字符?说什么不以 ab 结尾?

Edit: The original question doesn't seem to be a legit example for my case. So: how to handle more than one character? Say anything not ending with ab?

我已经能够解决这个问题，使用这个线程:

I've been able to fix this, using this thread:

.*(?:(?!ab).).$

尽管这样做的缺点是，它不匹配一个字符的字符串.

Though the downside with this is, it doesn't match a string of one character.

推荐答案

你不给我们语言，但如果你的正则表达式风格支持 看看断言背后，这就是你所需要的:

You don't give us the language, but if your regex flavour support look behind assertion, this is what you need:

.*(?<!a)$

(?<!a) 是一个否定的后视断言，它确保在字符串(或带有 m 修饰符的行)结束之前，没有字符a".

(?<!a) is a negated lookbehind assertion that ensures, that before the end of the string (or row with m modifier), there is not the character "a".

在 Regexr 上查看

您也可以轻松地使用其他字符扩展它，因为这会检查字符串而不是字符类.

You can also easily extend this with other characters, since this checking for the string and isn't a character class.

.*(?<!ab)$

这将匹配不以ab"结尾的任何内容，在 Regexr 上查看

This would match anything that does not end with "ab", see it on Regexr

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