正则表达式:一次性获取没有扩展名的文件名? [英] Regex: Get Filename Without Extension in One Shot?

问题描述

我只想使用正则表达式获取文件名，所以我一直在尝试简单的事情，例如

I want to get just the filename using regex, so I've been trying simple things like

([^\.]*)

当然只有在文件名有一个扩展名时才有效.但如果是adfadsfads.blah.txt，我只想要adfadsfads.blah.我怎样才能用正则表达式做到这一点?

which of course work only if the filename has one extension. But if it is adfadsfads.blah.txt I just want adfadsfads.blah. How can I do this with regex?

关于大卫的问题，你为什么要使用正则表达式"，答案是为了好玩".其实我用的代码很简单

In regards to David's question, 'why would you use regex' for this, the answer is, 'for fun.' In fact, the code I'm using is simple

length_of_ext = File.extname(filename).length
filename = filename[0,(filename.length-length_of_ext)]

但我喜欢尽可能学习正则表达式，因为它总是出现在 Geek 鸡尾酒会上.

but I like to learn regex whenever possible because it always comes up at Geek cocktail parties.

推荐答案

试试这个:

(.+?)(\.[^.]*$|$)

这将:

• 捕获以点开头的文件名(例如 .logs 是名为 .logs 的文件，而不是文件扩展名)，这在 Unix 中很常见.
• 获取除最后一个点以外的所有内容:foo.bar.jpeg 获取foo.bar.
• 处理没有点的文件:secret-letter 为您提供 secret-letter.

• Capture filenames that start with a dot (e.g. .logs is a file named .logs, not a file extension), which is common in Unix.
• Gets everything but the last dot: foo.bar.jpeg gets you foo.bar.
• Handles files with no dot: secret-letter gets you secret-letter.

注意:正如评论者 j_random_hacker 所建议的那样，这与宣传的一样，但出于可读性目的，您可能希望在前面加上锚点.

Note: as commenter j_random_hacker suggested, this performs as advertised, but you might want to precede things with an anchor for readability purposes.

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