除引号中的单词外，在空格上拆分字符串 [英] Split string on spaces except words in quotes

问题描述

我有一个类似的字符串

$string = 'Some of "this string is" in quotes';

我想得到一个字符串中所有单词的数组，我可以通过这样做获得

I want to get an array of all the words in the string which I can get by doing

$words = explode(' ', $string);

但是我不想将引号中的单词分开，所以理想情况下最后的数组是

However I don't want to split up the words in quotes so ideally the end array will be

array ('Some', 'of', '"this string is"', 'in', 'quotes');

有人知道我该怎么做吗?

Does anyone know how I can do this?

推荐答案

您可以使用:

$string = 'Some of "this string is" in quotes';
$arr = preg_split('/("[^"]*")|\h+/', $string, -1, 
                   PREG_SPLIT_NO_EMPTY|PREG_SPLIT_DELIM_CAPTURE);
print_r ( $arr );

输出:

Array
(
    [0] => Some
    [1] => of
    [2] => "this string is"
    [3] => in
    [4] => quotes
)

正则表达式分解

("[^"]*")    # match quoted text and group it so that it can be used in output using
             # PREG_SPLIT_DELIM_CAPTURE option
|            # regex alteration
\h+          # match 1 or more horizontal whitespace

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