以简单的方式包含重音字符的好正则表达式是什么? [英] What's a good regex to include accented characters in a simple way?

问题描述

现在我的正则表达式是这样的:

Right now my regex is something like this:

[a-zA-Z0-9] 但它不像我想要的那样包含重音字符.我也想包含 - ' .

[a-zA-Z0-9] but it does not include accented characters like I would want to. I would also like - ' , to be included.

推荐答案

重音字符:DIY字符范围减法

如果您的正则表达式引擎允许(并且许多引擎允许)，这将起作用:

If your regex engine allows it (and many will), this will work:

(?i)^(?:(?![×Þß÷þø])[-'0-9a-zÀ-ÿ])+$

请参阅演示(您可以添加字符进行测试).

Please see the demo (you can add characters to test).

说明

• (?i) 设置不区分大小写模式
• ^ 锚断言我们在字符串的开头
• (?:(?![×Þß÷þø])[-'0-9a-zÀ-ÿ]) 匹配一个字符...
• 前瞻(?![×Þß÷þø]) 断言字符不是括号中的字符之一
• [-'0-9a-zÀ-ÿ] 允许在宽重音范围内使用破折号、撇号、数字、字母和字符，我们需要从中减去
• + 匹配一次或多次
• $ 锚断言我们在字符串的末尾

• (?i) sets case-insensitive mode
• The ^ anchor asserts that we are at the beginning of the string
• (?:(?![×Þß÷þø])[-'0-9a-zÀ-ÿ]) matches one character...
• The lookahead (?![×Þß÷þø]) asserts that the char is not one of those in the brackets
• [-'0-9a-zÀ-ÿ] allows dash, apostrophe, digits, letters, and chars in a wide accented range, from which we need to subtract
• The + matches that one or more times
• The $ anchor asserts that we are at the end of the string

参考

扩展 ASCII 表

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