正则表达式*不*匹配任何字符 [英] Regex to *not* match any characters

问题描述

我知道这是一个很奇怪的目标，但是为了快速修复我们的一个系统，我们确实需要不过滤任何输入并让损坏进入系统.

I know it is quite some weird goal here but for a quick and dirty fix for one of our system we do need to not filter any input and let the corruption go into the system.

我当前的正则表达式是\^.*"

My current regex for this is "\^.*"

问题在于它没有按计划匹配字符......但是对于一个匹配它确实有效.使它不起作用的字符串是 ^@jj (基本上任何有 ^ ... 的东西).

The problem with that is that it does not match characters as planned ... but for one match it does work. The string that make it not work is ^@jj (basically anything that has ^ ... ).

现在不匹配任何字符的最佳方法是什么?我正在考虑删除 \ ，但只有这样做才会将not"转换为start with"...

What would be the best way to not match any characters now ? I was thinking of removing the \  but only doing this will transform the "not" into a "start with" ...

推荐答案

^ 字符并不意味着不是"，除了在字符类中 ([]).如果你不想匹配任何东西，你可以使用匹配任何东西的否定前瞻:(?!.*).

The ^ character doesn't mean "not" except inside a character class ([]). If you want to not match anything, you could use a negative lookahead that matches anything: (?!.*).

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