如何检查字符串是否与 Scala 中的正则表达式完全匹配? [英] How to check whether a String fully matches a Regex in Scala?

问题描述

假设我有一个正则表达式模式，我想将许多字符串与之匹配.

Assume I have a Regex pattern I want to match many Strings to.

val Digit = """\d""".r

我只想检查给定的字符串是否与正则表达式完全匹配.在 Scala 中执行此操作的好方法是什么?

I just want to check whether a given String fully matches the Regex. What is a good and idiomatic way to do this in Scala?

我知道我可以在正则表达式上进行模式匹配，但是在这种情况下这在语法上不是很令人满意，因为我没有要提取的组:

I know that I can pattern match on Regexes, but this is syntactically not very pleasing in this case, because I have no groups to extract:

scala> "5" match { case Digit() => true case _ => false }
res4: Boolean = true

或者我可以回到底层的 Java 模式:

Or I could fall back to the underlying Java pattern:

scala> Digit.pattern.matcher("5").matches
res6: Boolean = true

这也不优雅.

有更好的解决方案吗?

推荐答案

回答我自己的问题我将使用pimp my library pattern"

Answering my own question I'll use the "pimp my library pattern"

object RegexUtils {
  implicit class RichRegex(val underlying: Regex) extends AnyVal {
    def matches(s: String) = underlying.pattern.matcher(s).matches
  }
}

并像这样使用它

import RegexUtils._
val Digit = """\d""".r
if (Digit matches "5") println("match")
else println("no match")

除非有人想出更好的(标准)解决方案.

unless someone comes up with a better (standard) solution.

注意事项

• 我没有拉皮条 String 来限制潜在副作用的范围.

• I didn't pimp String to limit the scope of potential side effects.

unapplySeq 在这种情况下读起来不太好.

unapplySeq does not read very well in that context.

这篇关于如何检查字符串是否与 Scala 中的正则表达式完全匹配?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！