至少有一个非空白 [英] Having at least one-nonwhitespace

问题描述

str 如果括号中至少包含一个非空格，则必须为真:

str must be true if it has at least one non-whitespace enclosed in the parenthesis:

str = (a)
str = ( as bs)
str = (as e)

如果根本没有空格则为 false

and false if it has non-whitespace at all

str = (   )

我不确定我是否可以做到 + 但这个条件也传递了 0 个非空格.请更正.

Im not sure if i can do that + but this condition is also passing the 0 non-whitespaces. Correct it please.

/^\([\S+\s*]+\)$\.test(str)/

推荐答案

你可以使用这个:

/^\(.*\S.*\)$/.test(str)

这匹配任何字符，然后是一个非空白字符(这使得它至少有一个非空白字符)，然后是任何字符直到结束.

This matches any character, then a non-whitespace character (that makes it at least one non-whitespace character), and then any character till the end.

这篇关于至少有一个非空白的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！