Python正则表达式匹配引号之间的文本 [英] Python regex match text between quotes

问题描述

在以下脚本中，我想提取双引号 (") 之间的文本.但是，python 解释器并不满意，我不知道为什么...

In the following script I would like to pull out text between the double quotes ("). However, the python interpreter is not happy and I can't figure out why...

import re

text = 'Hello, "find.me-_/\\" please help with python regex'
pattern = r'"([A-Za-z0-9_\./\\-]*)"'
m = re.match(pattern, text)

print m.group()

输出应该是find.me-/\.

推荐答案

match 从文本的开头开始搜索.

match starts searching from the beginning of the text.

改用search:

#!/usr/bin/env python

import re

text = 'Hello, "find.me-_/\\" please help with python regex'
pattern = r'"([A-Za-z0-9_\./\\-]*)"'
m = re.search(pattern, text)

print m.group()

match 和 search 在匹配失败时返回 None.

match and search return None when they fail to match.

我猜你从 python 得到 AttributeError: 'NoneType' object has no attribute 'group':这是因为你假设你会匹配而不检查 re.match 的返回.

I guess you are getting AttributeError: 'NoneType' object has no attribute 'group' from python: This is because you are assuming you will match without checking the return from re.match.

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