使用python regex删除括号之间的内容 [英] remove content between parentheses using python regex

问题描述

我有一个像 -

{[a] abc (b(c)d)}

我想删除这些括号[]和(())之间的内容.所以输出应该是 -

I want to remove the content between these bracket [] and (()). so the output should be -

 abc

我删除了括号之间的内容，但无法删除此[]之间的内容我试过下面的代码 -

I removed the content between parentheses but could not remove the content between this [] I have tried below code -

import re

with open('data.txt') as f:
    input = f.read()
    line = input.replace("{","")
    line = line.replace("}","")
    output = re.sub(r'\(.*\)', "", line)
    print output

输出是 -

[a] abc

在我的代码中，我首先替换 {} ，然后从 () 中删除内容.我想在 output = re.sub(r'\(.*\)', "", line) 这一行中添加 \[.*\] .但找不到办法做到这一点.我还在学习python.所以我正面临这个问题.请帮忙.

In my code first I replace the {} and then remove the content from () . I want to add \[.*\] in output = re.sub(r'\(.*\)', "", line) this line . But could not find a way to do this. I am still learning python. So I am facing this problem. please help.

推荐答案

您可以检查字符串是否包含 [, ], () 或 [no_brackets_here] 子串并在匹配时删除它们.

You may check if a string contains [, ], (<no_parentheses_here>) or [no_brackets_here] substrings and remove them while there is a match.

import re                                    # Use standard re
s='{[a] abc (b(c)d)}'
rx = re.compile(r'\([^()]*\)|\[[^][]*]|[{}]')
while rx.search(s):                          # While regex matches the string
    s = rx.sub('', s)                        # Remove the matches
print(s.strip())                             # Strip whitespace and show the result
# => abc

查看 Python 演示

它也适用于成对的嵌套 (...) 和 [...].

It will also work with paired nested (...) and [...], too.

模式详情

• \([^()]*\) - (，然后是除 ( 和 ) 之外的任何 0+ 个字符，然后是 )
• | - 或
• \[[^][]*] - [，然后是除 [ 和 ] 之外的任何 0+ 个字符/code>，然后 ]
• | - 或
• [{}] - 匹配 { 或 } 的字符类.

• \([^()]*\) - (, then any 0+ chars other than ( and ), and then )
• | - or
• \[[^][]*] - [, then any 0+ chars other than [ and ], and then ]
• | - or
• [{}] - a character class matching { or }.

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