通过一个正则表达式以任何顺序匹配多个单词 [英] Match multiple words in any order via one regex

问题描述

如标题中所述，我想要正则表达式，它将根据我的查询"按顺序给出结果.

as stated in heading I want regex which will give me results in order based on my 'query'.

line='VERSION="OTHER" POWER="LOW" FREQ="OFF" MAXTUN="BLER"'**

示例 1:

re.findall(r'FREQ="(.*?)"|VERSION="(.*?)"', line, re.MULTILINE)

输出为:

[('', 'OTHER'), ('OFF', '')]

我更喜欢的期望输出是这样的:

And desired output I prefer is something like:

['OFF', 'OTHER']

示例 2:

re.findall(r'VERSION="(.*?)"|FREQ="(.*?)"', line, re.MULTILINE)

输出是一样的:

[('', 'OTHER'), ('OFF', '')]

我更喜欢的期望输出是这样的:

And desired output I prefer is something like:

['OTHER', 'OFF']

有什么建议吗?

附言请不要问我想达到什么目的，并告诉我可能有更好的方法，除非您对此有疑问.

P.S. Please don't ask me what I want to achieve and tell me that there is maybe better way, only if you have some question regarding this.

谢谢！

推荐答案

您可以利用非捕获交替组来匹配 VERSION 或 FREQ(可选地以一个词边界，看看它是否符合你的要求):

You may leverage a non-capturing alternation group to match either VERSION or FREQ (optionally preceded with a word boundary, just check if it meets your requirements):

\b(?:VERSION|FREQ)="(.*?)"

查看正则表达式演示

详情

• \b - 前导词边界
• (?:VERSION|FREQ) - VERSION 或 FREQ
• =" - =" 子字符串
• (.*?) - 第 1 组(findall 的实际输出):除换行符以外的任何 0+ 个字符，尽可能少
• " - 双引号.

• \b - a leading word boundary
• (?:VERSION|FREQ) - either VERSION or FREQ
• =" - a =" substring
• (.*?) - Group 1 (the actual output of findall): any 0+ chars other than line break chars, as few as possible
• " - a double quote.

查看 Python 演示:

import re
line='VERSION="OTHER" POWER="LOW" FREQ="OFF" MAXTUN="BLER"'
print(re.findall(r'\b(?:VERSION|FREQ)="(.*?)"', line))
# => ['OTHER', 'OFF']

也许更好的主意是捕获键值对并将它们映射到字典:

A better idea, perhaps, is to capture key-value pairs and map them to a dictionary:

import re
line = 'VERSION="OTHER" POWER="LOW" FREQ="OFF" MAXTUN="BLER"'
results = re.findall(r'(VERSION|FREQ)="(.*?)"', line)
print(dict(results))
# => {'FREQ': 'OFF', 'VERSION': 'OTHER'}

请参阅 Python 演示.

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