如何使用正则表达式用空格替换字符之间的破折号 [英] How to replace dash between characters with space using regex

问题描述

我想使用正则表达式用空格替换字母之间出现的破折号.例如将 ab-cd 替换为 ab cd

I want to replace dashes which appear between letters with a space using regex. For example to replace ab-cd with ab cd

以下匹配字符-字符序列，但也会替换字符 [即ab-cd 结果是 a d，而不是我想要的 ab cd]

The following matches the character-character sequence, however also replaces the characters [i.e. ab-cd results in a d, rather than ab cd as i desire]

 new_term = re.sub(r"[A-z]\-[A-z]", " ", original_term)

我如何调整上述内容以仅替换 - 部分?

How i adapt the above to only replace the - part?

推荐答案

您需要捕获 - 中的 before 和 after 字符以一组并使用它们进行替换，即:

You need to capture the characters before and after the - to a group and use them for replacement, i.e.:

import re
subject = "ab-cd"
subject = re.sub(r"([a-z])\-([a-z])", r"\1 \2", subject , 0, re.IGNORECASE)
print subject
#ab cd

<小时>

演示

http://ideone.com/LAYQWT

正则表达式解释

([A-z])\-([A-z])

Match the regex below and capture its match into backreference number 1 «([A-z])»
   Match a single character in the range between "A" and "z" «[A-z]»
Match the character "-" literally «\-»
Match the regex below and capture its match into backreference number 2 «([A-z])»
   Match a single character in the range between "A" and "z" «[A-z]»

\1 \2

Insert the text that was last matched by capturing group number 1 «\1»
Insert the character " " literally « »
Insert the text that was last matched by capturing group number 2 «\2»

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