preg_match 所有单词以@ 开头? [英] preg_match all words start with an @?

问题描述

我对正则表达式不是很熟悉，所以我不得不问你:

i'm not very firm with regular Expressions, so i have to ask you:

如何使用 PHP 找出字符串是否包含以 @ 开头的单词??

How to find out with PHP if a string contains a word starting with @ ??

例如我有一个像这是给@codeworxx"这样的字符串???

e.g. i have a string like "This is for @codeworxx" ???

我很抱歉，但我没有起点:(

I'm so sorry, but i have NO starting point for that :(

希望能帮到你.

谢谢，萨沙

好的，谢谢你的结果 - 但我犯了一个错误 - 如何在 eregi_replace 中实现???

okay thanks for the results - but i did a mistake - how to implement in eregi_replace ???

$text = eregi_replace('/\B@[^\B]+/','<a href="\\1">\\1</a>', $text);

不起作用??！?

为什么?我不需要输入与模式相同的表达式吗?

why? do i not have to enter the same expression as pattern?

推荐答案

Match 任何东西，在 @ 前面有一些空格，后面跟着一些不是空格的东西:

Match anything with has some whitespace in front of a @ followed by something else than whitespace:

$ cat 1812901.php

<?php
    echo preg_match("/\B@[^\B]+/", "This should @match it");
    echo preg_match("/\B@[^\B]+/", "This should not@ match");
    echo preg_match("/\B@[^\B]+/", "This should match nothing and return 0");
    echo "\n";
?>

$ php 1812901.php 
100

这篇关于preg_match 所有单词以@ 开头?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！